Python packet closure function

Closed Package

Closures: Closures in Python are defined (interpreted) from the expression form as:

If in an intrinsic function, a reference is made to a variable that is in an outer scope (but not at the global scope), then the intrinsic function is considered a closure (closure).

Look at a function first:

def func1 ()     def func2 ()         a = 1         return a     func2 ()

Because there are nested functions inside the function,
nested function definitions: functions defined inside cannot be called globally
So there's a closure problem.
What's the problem?
Is that func1 can't get FUNC2 's variable A.
How do you get it?
We know that a function is the first class of objects (the first kind of object you can use as a variable), you can put the variable in the FUNC1 (FUNC2) through return

def func1 ()     def func2 ()         a = 1         return a     return func2  x = func1 ()    #这样就拿到了func2 and assigned to the variable x x ()        # x () equivalent to FUNC2 ()      See    If you get a return value a   so you get the FUNC2 variable a  and if: def func1 (para1)     para1     def func2 ()         A = 1         return para1 + a     return Func2  func1 (5)    #如果把5传给func1    will pack def FUNC2 this function,     # Note:             def func2 ()                 a = 1 return                 1 + a func1 (5) ()  #等同于func2 () #就变相调用函数func2 ()  Gets the return value of 6 print (FUNC1 (5 ) ()  # 6  #如果func1 (8),   then Func2 packaged:         def func2 ()             a = 1             return 8 + a #每次调用func1, It will return (package) A new closure instance so: closure = function + Reference environment

　　

Python packet closure function