Python Saturday study record 20171118 Day record one

Study Notes

1. Generate a large string of 1 to 50 with a space between each number

result = ' ' Store results

For I in Range (1,50,1): #遍历1-to 50 data

if i = =: #为了结尾出现空格这样处理

result = result + str (i) #把结果存放到变量中去

result = result + str (i) + "" #拼接成功

Print result

============

2, using while statistics of the sentence there are several numbers, dynamic input

Content = raw_input ("Please input a sentenece:\n") #输入

result = 0 #定义结果存放

index = 0 #定义索引

While index <= len (content)-1: #判断长度

If Content[index] in "0123456789": #判断是否在数字里面

Result + = 1 #如果在就加一存放结果

Index + = 1 #下标往移动

Print result #打印结果

==================

Third, the reverse of a list element exists in a new list

A = [1,3,4,5,6]

b = [] #保存结果

For I in a: #循环输出a

B.insert (0,i) #始终从第一个插入数据

Print B

========================

Enter four number flashback sort: and sort

Number = 0

b = []

c = []

For I in range (4):

Number = Int (raw_input ("Please enter hour\n"))

B.insert (0,number) #往第一个里面增加倒叙

C.append (number) #往数组里面增加,

C.sort () #调用函数进行排序

Print B

Print C

==========

Output 26 lowercase letters

result = []

For I in range (97,97 + 26):

Result + CHR (i)

Print result

Output Capital letters:

result = []

For I in range (65,65 + 26):

Result + CHR (i)

Print result

Uppercase and lowercase letters output together

result = ' #保存结果

For I in range (65,65 +): #从65到26为大写

Result + CHR (i) + CHR (i + +) #从97倒128小写

Print result

==============

Determine how many letters are included in a sentence

Content = raw_input (' Please input a sentence\n ')

Letter_count = 0

For s in content:

If s not in ' 0123456789 ':

Letter_count + = 1

Print Letter_count

=====================

Import string

sentence = raw_input ("Input youtsentence\n") # Storage location

letter_nbr=0 # counter

For i in sentence:

if I instring.letters # built-in functions

Letter_nbr+=1 # Count

Print LETTER_NBR

==========================

Encryption:

Letters = raw_input ("Please input some letter to encode:")

Encode_letters = ""

For s in letters:

if (S >= "a" and S < "W") or (S >= "a" and S <= "W"):

Encode_letters + = Chr (ord (s) + 4)

elif s >= "W" and S <= "Z":

Encode_letters + = Chr (ord (s)-Ord ("W") + 97)

elif s >= "W" and S <= "Z":

Encode_letters + = Chr (ord (s)-Ord ("W") + 65)

Else

Print "Some content is not letter! Please try agan! "

Continue

Print Encode_letters

=========

Judging character types

>>> a = ' dd '

>>> isinstance (A,int)

False

>>> isinstance (a,list)

False

>>> isinstance (A,STR)

True

>>> B = [' 1w ', 3, ' de ', 233]

>>> isinstance (b,list)

True

>>> isinstance (b,tuple)

False

>>> isinstance (b,dict)

False

>>> A = 1

>>> B = 0

>>> BOOL (1)

True

>>> BOOL (b)

False

>>>

Python Saturday study record 20171118 Day record one