The Java implementation iterates through each letter of a string (summary)

Basics: Keep in mind the various methods of string manipulation:

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?        String s = "AAALJLFEAKDSFLKJSADJAEFDSAFHAASDASD";                Number of occurrences        int num = 0;                 Loop through each character to determine if it is a character a, if yes, the number of increments for        (       //Input code                   )        {            //To get each character, to determine whether the character a            if (     //Input code            ) {                //Cumulative statistics Count                num++;             }        }        System.out.println ("The number of occurrences of character a:" + num);?

1.

? int num = 0;        for (     int i=0;i<s.length (); i++         )        {            if (  s.charat (i) = = ' A ') {                num++;             }        }?

2. Using the properties of an array of bytes arrays:

? int num = 0;        Byte[] Bytes=s.getbytes ();        for (  int i=0;i<bytes.length;i++       )        {                        if (bytes[i]== ' a ') {                num++;             }        }?

3. Using the array char

?        Char[] C=s.tochararray ();           for (   int i=0;i<c.length;i++    )        {            if (    c[i]== ' a '    ) {                num++;             }        }?

4. Using the substring (startindex,endindex) string

? for (   int i=0;i<s.length (); i++  )        {            String s1=s.substring (i,i+1);            if (   s1.equals ("a")) {  //Note this place cannot be ' a '.                num++;             }        }?

The

Java implementation iterates through each letter of a string (summary)