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DescriptionHere is read the "Effective Java Chinese version of the second edition" of the Reading notes, here will record some personal feeling a little bit important content, convenient for later review, may be due to personal strength reasons caused by misunderstanding, if found welcome to point out. Some individuals do not understand that will be marked with a slash.The first chapter is the introduction,
(Javamemory model, the Java memory model) in the cache, register to main memory writeback order, the second and third Order of the above is not guaranteed. In other words, the order of execution may be either 1-3-2 or either. If the latter, and before the execution of 3, 2 is not executed, was switched to thread B, this time instance because already in thread A has been executed in the 3rd, instance is alr
;ImportOrg.testng.annotations.BeforeMethod;Importorg.openqa.selenium.By;ImportOrg.openqa.selenium.JavascriptExecutor;ImportOrg.openqa.selenium.WebDriver;Importorg.openqa.selenium.WebElement;ImportOrg.openqa.selenium.chrome.ChromeDriver;ImportOrg.testng.annotations.AfterMethod; Public classScrollbarapi {webdriver driver; String BaseUrl; //Slide the scroll bar to the bottom of the page@Test (priority=0) Public voidf () {((javascriptexecutor) driver). Executescript ("Window.scrollto (0,documen
data;public lnode next;}Algorithm implementation:public class Linklistutli {public static void Deleterepeatvalue (Lnode L) {//If the single-linked list is empty, or if there is only a header node, or if there is only one element behind the head node. There is no possibility of duplicate values if (l==null| | l.next==null| | L.next.next==null) return; Lnode p=l;//The previous node of the current access node Lnode q=l.next;//the currently visited node
/** * Title: * There are a pair of rabbits, from the 3rd month after birth, each month has a pair of rabbits, the rabbit long to the third month after the birth of a pair of rabbits each month. * If the rabbit is not dead, ask after month months, how many rabbits total? */public class Fibonacci {//month static Integer month = 3;//NOTE: month > 0public static void Main (string[] args) {Integer pair = f (month); System.out.println ("A: after" + month +
handy;2, through reading the document and the actual use, mastered the basic usage of jsoup;3, enhance the Java programming ability. The insufficiency of this experiment:1, the code has redundancy, the next time you can use a lot of encapsulation and inheritance, make the code more readable;2, did not do highlight;3, only the analysis of 3 pages, after perfect can be more analysis of several pages (in fact, similar principles), increase the degree of
Java code to implement:/** * Enter an array of integers with positive and negative numbers in the array. One or more consecutive integers in an array make up a sub-array. * The maximum value of all sub-arrays is evaluated. Requires time complexity O (n) */package swordforoffer;/** * @author Jinshuangqi * * August 8, 2015 */public class E31greatestsumofsubarrays {Pub Lic Integer findgreatestsum (int[] arr) {if (arr.length ==0) return null; int greate
link Address: Commodity barcode (Jbarcode)This article is copyrighted by the author and the blog Park is shared, welcome reprint, but without the author's consent must retain this paragraph, and in the article page obvious location to the original linkOriginal link: http://www.cnblogs.com/yuchuan/p/JBarcode2.htmlIf you think this article is good, may wish to recommend, let more readers get the harvest.If you have any other ideas, may wish to leave a message, we all discuss together. Three peopl
10,5,7. Next we take the node with a value of 10 from the data container. Notice that the node value of 10 is 5, 7, the node is placed in the container first, and then the two nodes are removed first, this is what we usually say first in first out, so it is not difficult to see that this container should be a queue. Because nodes with a value of 5,7,9,11 have no child nodes, they can be printed in turn.By analyzing specific examples, we can find the rules for printing binary trees from top to b
sorted.1 Public int[] Chosesort (int[] intarr) { 2 for(inti=0;i){ 3 intLowindex =i; 4 5 for(intj=i+1;j){ 6 if(intarr[j]Intarr[lowindex]) { 7Lowindex =J; 8 } 9 } Ten One //swaps the current first element with the smallest element in the sequence that follows it, that is, placing the smallest element in the front-end A inttemp =Intarr[i]; -Intarr[i] =Intarr[lowindex]; -Intarr[lowindex] =temp; the } - - ret
node in a single-linked list, then the single-linked list does not need to be reversed, and if there is only one element in the single-linked list, its position will not change after the reverse, so it can not be reversed. When there are 2 or two or more elements in a single-linked list, it is broken from the 1th element, so that its next is empty, then the 2nd element is accessed to the nth element, and when one of the elements is accessed, it is inserted into the
==N2) + "\ T" + "N1Exercise 4: (3) write a program that uses two nested for loops and the remainder operator (%) to detect and print a prime number (an integer that can be divisible only by itself and 1 and not by other numbers). public static void Main (string[] args) {test (33);} public static Boolean test (int num) {for (int i=2;iExercise 5: (4) Repeat Exercise 10 in chapter 3rd, instead of using the integer.tobinarystring () method, use the
); SYSTEM.OUT.PRINTLN (path); } } Through this time of optimization, let me know the importance of the source code, want to know something in-depth, you need to understand the internal, with learning knowledge to arm themselves, rookie study, Big Bird do not spray, just record, by the way to those who do not love their brains, if you like me this way, please click on the lower right corner of the recommendation,Sleep, Xiaoxifu exercise also finished ...Attached: Pre
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