sql query to remove duplicates

duplicate field name,address, which requires the result set to be unique for both fieldsSelect Identity (int,1,1) as Autoid, * into #Tmp from TableNameSelect min (autoid) as autoid into #Tmp2 from #Tmp Group by name,autoidSELECT * from #Tmp where autoid on (select Autoid from #tmp2)The last select is the result set that name,address not duplicate (but one more autoid field, which can be written in the SELECT clause without this column in the actual write)FourDuplicate querySELECT * FROM tablena

; }The JSON configuration file specifies that the required fields are used as aliases, but if the alias is a number or a special character, Oracle is not recognized, if the alias is enclosed in double quotation marks, Orace but the JSON file is not recognized, so I use the most low method, Add all aliases to a c_ so that the database is recognized.Take a look at the Removesql method:/*** Remove SQL statemen

Remove userid group_concat (title) group_concat (oid) group_concat (statue) from the same field in SQL query) 1 warranty, warranty, tutorial sp111, sp234, sp134 1 0 1 Based on this statue attribute, if the content with the same title value is 1, it will be removed if it is reserved as 0. Userid group_concat (title) group_concat (oid) group_concat (statue) 1 w

can be only one primary key for 11 tables, and a unique index may build multiple.The 2 primary key can be used as a foreign key for other tables.3 The primary key is not nullable, and the unique index can be null. Clustered index: A directory in which data within a table is arranged according to certain rules. Because of this, there is only one focus index in a table. To this we should note that the "primary key is the focus index" is extremely wrong, is a focus on the index of a waste. (althou

Index: [Leetcode] leetcode key index (C++/JAVA/PYTHON/SQL)Github:https://github.com/illuz/leetcode026. Remove duplicates from Sorted Array (easy)links：Title: https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array/Code (GitHub): Https://github.com/illuz/leetcode

([Idx_noncls_include_ Exceptorderid])' shenzhen ' GO As you know, nonclustered index columns do not need to contain columns that create a clustered index, so what exactly is the fact? Conclusion: In fact, there is no need for any nonclustered index column to contain the column that created the clustered index, because the column that creates the clustered index is part of the nonclustered Index collection column, which means that the nonclustered index collection column contains the clustered

(). ToList ();var CategoryReviewwing2 = categoryreviewwing1.groupby (o = = new {O.style}). ToList (). Exists (g = G.count () > 1);var CategoryReviewwing2 = categoryreviewwing1.groupby (o = = new {O.style}). Where (g = G.count () >= 1). ToList ();var CategoryReviewwing2 = categoryreviewwing1.groupby (o = = new {O.style}). Where (g = G.count () >= 1). Count ();It notes how much of the duplicate data the query has, and the second one is to the list coll

found that Prev is Fakenode node initially. Because the Fakenode node initially points to the head node.Runtime:8ms/** * Definition forsingly-linked list. * struct ListNode {*intVal * ListNode *Next; * ListNode (intx): Val (x),Next(NULL) {} * }; */classSolution { Public: listnode* deleteduplicates (listnode* head) {ListNode * fakenode=NewListNode (0); Fakenode->Next=head; ListNode *prev=fakenode; while(head!=NULL) {if(head->Nexthead->val==head->Next->val) {intvalue=head->val; while(Headhead-

1.1 million recorded text files, remove the top 10 duplicates. Sample text: 098 123 234 789 ...... 234 678 654 123 Seeking Ideas Reply to discussion (solution) Import into the table, and then use SQL statistics to not know if it is feasible. You can try it. Import into the table, and then use SQL statistics

Recently, bloggers want to use Python to remove repetitive or similar SQL when analyzing database slow query logs, so you don't have to look at a lot of similar SQL. Repeating the same data is simpler and can be done using the built-in set command. For example: L1 = [' A ', ' B ', ' C ', ' d ', ' e ', ' A ', ' B ', '

U.userid=ur. User_ID left joins Base_roleinfor R on R.role_id=ur. role_id) t where t.userid=t1. USERID for XML Path (")) as RoleName from (select R.role_name,u.userid,u.username,u.truename from base_userinfor u left Joi n base_userrole ur on u.userid=ur. User_ID left joins Base_roleinfor R on R.role_id=ur. role_id) T1 GROUP by Userid,truename,usernameLook at the results of the query, not what we want.It is important to pay attention to the following

(A.PEOPLEID,A.SEQ) in (select Peopleid,seq from Vitae GROUP by PEOPLEID,SEQ have count (*) > 1)and rowID not in (select min (rowid) from Vitae GROUP by PEOPLEID,SEQ have Count (*) >1)5. Find redundant duplicate records (multiple fields) in the table, not including the smallest ROWID recordsSELECT * FROM Vitae awhere (A.PEOPLEID,A.SEQ) in (select Peopleid,seq from Vitae GROUP by PEOPLEID,SEQ have count (*) > 1)and rowID not in (select min (rowid) from Vitae GROUP by PEOPLEID,SEQ have Count (*) >

fromVitaeGroup byPeopleid,seq having Count(*)> 1) androwID not inch(Select min(ROWID) fromVitaeGroup byPeopleid,seq having Count(*)>1) 5, find redundant duplicate records (multiple fields) in the table, and do not contain ROWID minimum recordsSelect * fromVitae awhere(A.PEOPLEID,A.SEQ)inch(SelectPeopleid,seq fromVitaeGroup byPeopleid,seq having Count(*)> 1) androwID not inch(Select min(ROWID) fromVitaeGroup byPeopleid,seq having Count(*)>1) 6. Remo