sudoku 3x3

I usually like to play the sudoku game. I suddenly wanted to use a program to automatically solve the problem yesterday. The idea is to trace back and keep testing. The program code is as follows: 1 # include 23 /*4 {, 1 },5 {, 6 },6 {9, 0, 0 },7 {1, 2, 5, 0, 6, 0, 3, 4, 7 },8 {, 6, 0, 0, 9, 8, 5 },9 {, 9, 0, 2 },10 {, 0, 0, 4 },11 {, 9 },12 {6, 4, 0 }};13 */1415 int data [9] [9] = {16 {, 0 },17 {, 7 },18 {, 0 },19 {5, 0, 0, 0, 0, 0, 0 },20 {, 0 },21

Today the idea is determined, roughly for the following structure:1. Define the data in the game and initialize the lattice data.2. Define touch events.In the view class, overwrite the Ontouchevent (Motionevent event) method.3, inherit the dialog class, customize a dialog.4, do the above preparation, we can re-view class, the game layout, and to operate.5. Call the MyView object in the main class.Estimated time: 5 days, each day to complete the encoding of a class.Today's content:The class of th

{ - to if(i==Bayi) + { -n=Bayi; the return; * } $ inty=i/9, x=i%9;Panax Notoginseng if(a[y][x]==0) - { the for(intI=1; i9; i++) + { A if(check (y,x,i)) the { +a[y][x]=i; -i++; $ DFS (); $i--; - if(n==Bayi) - { theI=Bayi; - Break;Wuyi } thea[y][x]=0; - } Wu if(

canvas.drawrect (0, 0, getwidth (), getheight (), Paint );//define the Brush object and draw the grid line paint Darkpaint = new paint ();d Arkpaint.setcolor (Getresources (). GetColor (R.color.shudu_dark)); Paint Hilitepaint = new paint (); Hilitepaint.setcolor (Getresources (). GetColor (R.color.shudu_hilite)); Paint Lightpaint = new paint (); Lightpaint.setcolor (Getresources (). GetColor (R.color.shudu_light));//Draw nine lattice for (int i = 0 ; iCall the MyView object in the main class.Pa

} + } A return false; the } + intMain () { - intT, I, J; $ CharC; $scanf"%d", t); - while(t--){ - bk.clear (); thememset (Row_f,0,sizeof(Row_f)); -memset (Col_f,0,sizeof(Col_f));Wuyimemset (Block_f,0,sizeof(Block_f)); the for(i =0; I 9; ++i) { - for(j =0; J 9; ++j) { WuCIN >>C; -G[I][J] = C-'0'; About if(!G[i][j]) $ Bk.push_back (Blank (i, j)); - Else -Setnum (i, J, G[i][j],1); - } A } +

); theha[x][i]=0; -li[y][i]=0; Wuxi[(x1)/3*3+ (Y1)/3][i]=0; - } About } $ intMain () - { - for(intI=1; i9; i++) - { A for(intj=1;j9; j + +) + if(j%3) the { -scanf"%s", ch); $ if(ch[0]=='') thebh[i][j+1]=1; the Else thebh[i][j+1]=0; the } - if(i%3) in for(intj=1; j9; j + +) the { thescanf"%s", ch); About if(ch[0]=='^') thebl[i+1][j]=1; the Else t

translation数独板被部分填充，空格部分用‘.‘来填充。一个部分填充的数组是否有效只需要看其填充的部分即可。OriginalCodeThe word was inscribed for a while, wrong ... Because the input is too lazy to make, directly read someone else's writing ...classSolution { Public:inta[9];BOOLIsvalidsudoku ( vectorvectorchar>> Board) {memsetA0,sizeof(a)); for(intI=0, j=0, row=0, col=0;i9; ++j,j==9? ++i,j=0, row=col=0:0) {if(board[i][j]!='. ') {if((1 -) Row)return false;Elserow|=1 -;if((1 -) a[i/3*3+j/3])return false;Elsea[i/3*3+j/3]|=1 -;

Idea: Record the number of each row in each column that has already appeared. Data is relatively weakIn addition POJ 3074 3076 must use pruning strategies. But to achieve more trouble, or after the DLX to do it againaccepted160k0ms#include POJ 2676/2918 Sudoku (DFS)

,0,sizeof(used)); $ for(intI=1; i9; i++) - { - Charstr[Ten]; -scanf"%s", str); A for(intj=0;j9; j + +) + { thea[i][j+1]=str[j]-'0'; - if(a[i][j+1]!=0) $ { thev[i][j+1]=1; the intx=a[i][j+1]; therow[i][x]=1; thecol[j+1][x]=1; -used[(I-1)/3+1[(j+1-1)/3+1][x]=1; in } the } the } About /* the for (int i=1;i the { the for (int j=1;j + printf ("\ n"); -

Publicclasssudokuverifier{privatebooleanis1to9row (int[][]a,int R) {int[]pos=newint[9];for (inti=0;iA Sudoku Verifier

#include #include #include #include using namespace STD;intmp[Ten][Ten],row[Ten][Ten],col[Ten][Ten],grid[Ten][Ten];intGetintXintY) {if(x>=1x3) {if(y>=1y3)return 1;Else if(y>=4y6)return 4;Else return 7; }Else if(46) {if(y>=1y3)return 2;Else if(y>=4y6)return 5;Else return 8; }Else{if(y>=1y3)return 3;Else if(y>=4y6)return 6;Else return 9; }}intDfsintXintY) {if(x==Ten)return 1;intflag=0Iif(Mp[x][y]) {if(y==9) Flag=dfs (x+1,1);ElseFlag=dfs (x,y+1);if(flag)return 1;Else return 0; }Else{ for(i=1;

Original title AddressBacktracking, nothing to say.1 BOOLrow[9][9];2 BOOLcol[9][9];3 BOOLgrid[9][9];4 BOOLmark[9][9];5 6 BOOLSolve (vectorChar> > board,intRintc) {7 if(r = =9)8 return true;9 if(Mark[r][c])Ten returnSolve (board, R + (c +1) /9, (c +1) %9); One for(inti =0; I 9; i++) { A if(!row[r][i] !col[c][i] !grid[(R/3) *3+ C/3][i]) { -Row[r][i] = Col[c][i] = grid[(R/3) *3+ C/3][i] =true; -BOARD[R][C] = i +'1'; the if(Solve (board, R + (c +1) /9, (c +1) %9)) -

Android games-Sudoku (2)> First, create a View class --> inherit SurfaceView and implement SurfaceHolder. callback interface --> SurfaceView. getHolder () obtains the SurfaceHolder object --> SurfaceHolder. addCallback (callback) adds a callback function --> SurfaceHolder. lockCanvas () Get the Canvas object and lock the Canvas --> Canvas painting --> SurfaceHolder. unlockCanvasAndPost (Canvas canvas) ends locking and submits changes to display the im

Question: 16*16. Train of Thought Analysis: Needless to say, it is useless. This is to say that the dancing links line is based on Enter 1 in the first column of the first row. Enter 2 in the second column of the first row. ...... Enter 15 in column 15th of the first row. Enter 1 in the second column of the first row. ...... The second line .... Column textiles are Put 1 In the first row and 2 in the first row ,.. Put 16th rows in 16... Put 1 In the first column .. Put 2 In th

There is nothing to say about searching. Pay attention to reading.Code: #include [Search] bzoj3109 [cqoi2013] New Sudoku

Continue. Today we are talking about reading and writing record files. Because the sudoku implemented on the Brew platform is a binary file, it is used directly on Android. We plan to implement two functions: loadtilist (), load the question library, first load the question library file in the resource, and then load it from the resource as a datainputstream. There are few lines of code, as shown below: public static Boolean loadtilist (mainactivity

number of color labels and the number of candidates O enhanced operations in common mode (non-candidate Mode) O added the function of manually adding candidates O preset nearly 50 thousand 17 initial number of sudoku questions O adjusted the copied steps O Add a new user manual to illustrate the operation methods and problem-solving skills O reduce the installation package size O added the function of checking new versions. 2. Problem corre

column to retrace the previous columnJ-= 2; Continue; } Else { //the first column goes backwards in the last rowi--; J= 8; Continue; } } //Check if it works if(Checkok (i, J)) {Count= 0;//Possible reset Counters } Else{Count++;//counter plus 1j--;//continue to } } }}//Initializefunctionchess () {creatchess ();//Create a chessboardChessinit ();//Initialize the bo

The basic framework of the The basic framework of backtracking algorithm isfunction name (int cnt) {for (){if () {}else{Function name (cnt+1);}}}Backtracking algorithm (solving arbitrary order Sudoku)

1. Click the "Settings" button on the main screen to enter. 　2. After opening the "Settings" interface, click on the "General" menu click on its details as shown. 3. After opening the generic option interface, pull down, locate the keyboard option, and then open 4. Open the "keyboard" option, then click the "Keyboard" option, open and click the first "Simplified Chinese" option 5. Setup Complete Friendly tips, ios7.1.2 nine Sudoku and iOS7 i