1018. Hammer and Scissors Cloth (20) (Math ah Zju_pat)

Title Link: http://www.patest.cn/contests/pat-b-practise/1018

Everyone should play "Hammer and Scissors Cloth" game: two people at the same time give gestures, the rule of victory:

Now give a record of the confrontation between two people, please count the wins, flat, negative number of both sides, and give the two sides what gesture of the greatest odds.

Input format:

Enter the 1th line to give the positive integer n (<=10^{5), which is the number of times the two sides clash. Then n lines, each row gives the information of a confrontation, that is, a, b both sides of the gesture given at the same time. C for "Hammer", J for "Scissors", B for "cloth", 1th letter for party A, 2nd for party B, 1 spaces in the middle.}

Output format:

Output 1th, 2 respectively give a, B wins, flat, negative times, the number between 1 spaces separated. The 3rd line gives two letters, representing the most winning gestures of A and b, with 1 spaces in the middle. If the solution is not unique, the solution with the smallest alphabetic order is output.

Input Sample:

10C JJ BC bb bb cc cc BJ BB CJ J

Sample output:

5 3 3 5B B

The code is as follows:

#include <cstdio>int main () {int n;    int a1=0,a2=0,a3=0;//A win, draw, B win int aj=0,ac=0,ab=0;//out what way to win multiple int bj=0,bc=0,bb=0;    Char x,y,blank;scanf ("%d", &n);        for (int i = 0; i < n; i++) {GetChar ();        scanf ("%c%*c%c", &x,&y);        if ((x== ' C ') && (y== ' J ')) {a1++; ac++; continue;}        if (x== ' J ') && (y== ' B ')) {a1++; aj++; continue;}        if ((x== ' B ') && (y== ' C ')) {a1++; ab++; continue;}        if ((x== ' C ') && (y== ' C ')) {a2++; continue;}        if (x== ' J ') && (y== ' J ')) {a2++; continue;}        if ((x== ' B ') && (y== ' B ')) {a2++; continue;}        if ((x== ' C ') && (y== ' B ')) {a3++; bb++; continue;}        if (x== ' B ') && (y== ' J ')) {a3++; bj++; continue;}    if (x== ' J ') && (y== ' C ')) {a3++; bc++; continue;}    }printf ("%d%d%d\n", a1,a2,a3);p rintf ("%d%d%d\n", A3,A2,A1);    if ((AB&GT;=AC) && (Ab>=aj)) printf ("B");    else if (AC >= AJ) printf ("C");    else printf ("J"); if ((bb>=BC) && (BB&GT;=BJ)) printf ("b\n");    else if (BC&GT;=BJ) printf ("c\n");    else printf ("j\n"); return 0;}

1018. Hammer and Scissors Cloth (20) (Math ah Zju_pat)