1.7.04 stone scissors cloth (character array), 1.7.04 Array

1.7.04 stone scissors cloth (character array), 1.7.04 Array
04: Stone scissors

Total time limit:

1000 ms

 

Memory limit:

65536kB

Description

Stone scissors are a guessing game. It originated in China and then spread to Japan, North Korea, and other places. With the continuous development of Asia-Europe trade, it spread to Europe and gradually swept the world in modern times. Simple and clear rules make stone scissors free from any rules and vulnerabilities to be drilled. Single gameplay matches luck and multiple rounds of gameplay matches the psychological game, this ancient game, stone scissors, is also used in two features: "unexpected" and "technology", and is favored by the people of the world.

Game Rules: Stone scissors, cloth bag stone, scissors.

Now, you need to write a program to determine the result of the stone scissors game.

Input

The input includes N + 1 rows:
The first line is an integer N, indicating that a total of N games were played. 1 <= N <= 100.
Each row of the next N rows contains two strings, indicating the choice of the game participant Player1 and Player2 (stone, scissors, or cloth ):
S1 S2
String S1 is separated by spaces. S2 can only be set to {"Rock", "Scissors", "Paper"} (case sensitive.

Output

The output includes N rows. Each row corresponds to a winner (Player1 or Player2), or the Tie is output when the game draws.

Sample Input

3Rock ScissorsPaper PaperRock Paper

Sample output

Player1TiePlayer2

Prompt

Rock is a stone, Scissors is a Scissors, and Paper is a cloth.

#include<stdio.h>int main(){  int i,n;  char s1[10],s2[10];  int s[101];  scanf("%d",&n);  getchar();  for(i=0;i<n;++i)  {    scanf("%s%s",s1,s2);    if(s1[0]==s2[0]) s[i]=0;    switch(s1[0])    {      case 'R': if (s2[0]=='S') s[i]=1;          else if(s2[0]=='P') s[i]=2;     　　　　break;　　　 case 'S': if (s2[0]=='R') s[i]=2;          else if(s2[0]=='P') s[i]=1;        break;  　　 case 'P': if (s2[0]=='R') s[i]=1;          else if(s2[0]=='S') s[i]=2;        break;    }  }  for(i=0;i<n;++i)    if(s[i]==0) printf("Tie\n");      else if (s[i]==1) printf("Player1\n");      else if(s[i]==2) printf("Player2\n"); return 0;    }

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