26: count the number of four digits that meet the condition.

26: count the number of four digits that meet the condition.
26: count the number of four digits that meet the condition

• View
• Submit
• Statistics
• Question

Total time limit:1000 ms Memory limit:65536kBDescription

Given a number of four digits, find the number that meets the following conditions:

The number in a single digit minus the number in a thousand digits, then the number in a hundred digits, and then the number in a ten digit are greater than zero.

InputThe input is two rows. The first row is n in four digits, and the second row is n in four digits. The number and number are separated by a space. (N <= 100)OutputThe output is a row containing an integer, indicating the number of four digits that meet the condition.Sample Input

5
1234 1349 6119 2123 5017

Sample output

3

SourceExercise (5-7)

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 #include<cmath>
 5 using namespace std;
 6 int main()
 7 {
 8     int n;
 9     cin>>n;
10     int tot=0;
11     for(int i=1;i<=n;i++)
12     {
13         int a;
14         cin>>a;
15         if((a%10-((a/1000)%10)-((a/100)%10)-((a/10)%10))>0)
16         tot++;
17     }
18     cout<<tot;
19     return 0;
20 }