A good string transcoding and decoding function (self-writing), string Function

A good string transcoding and decoding function (self-writing), string Function

function isString(variable) {  return Object.prototype.toString.call(variable).indexOf('String') != -1;}function isNumeric(variable) {  return !isNaN(parseFloat(variable)) && isFinite(variable);}function stringEncode(string) {  string = isString(string) || isNumeric(string) ? String(string) : '';  var code,    i = 0,    code_string = '',    len = string.length;  while(i < string.length) {    code = string.charCodeAt(i);    code_string += '' + String(code).length + code;    i++;  }  return code_string;}function stringDecode(code) {  var i = 0,    code_len,    decode_string = '';  code = String(code);  while(i < code.length) {    code_len = +code.charAt(i);    i++;    decode_string += String.fromCharCode(+code.substr(i, code_len));    i += code_len;  }  return decode_string;}

Write a function to copy string 2 to string 1. The strcpy function is not allowed;

Strlen (char * p) and strcmp (char * p1, char * p2):]

(1) String Length function:

Int strlen (char * p)
{
Int I = 0;
While (p [I]! = '\ 0 '){
I ++;
}
Return I;

}

(2) string replication functions:

// Assign all content indicated by p2 to p1
Void strcpy (char * p1, char * p2)
{
Int I = 0;
While (p2 [I]! = '\ 0 '){
P1 [I] = p2 [I];
I ++;
}
P1 [I] = '\ 0 ';

}

(3) string comparison functions:

Int strcmp (char * p1, char * p2)
{
Int I = 0;
While (p1 [I]! = '\ 0' & p2 [I]! = '\ 0 '){
If (p1 [I]-p2 [I])
Return p1 [I]-p2 [I];
I ++;

}
Return strlen (p1)-strlen (p2 );

}

(4) Finally, provide a main function for you to test, and attach the test cases and expected output results:]

Int main ()
{
Char * p1, * p2;
P1 = new char [1000];
P2 = new char [1000];
While (cin> p1> p2 ){

Cout <strlen (p1) <endl;
Cout <strlen (p2) <endl;
Cout <strcmp (p1, p2) <endl;

Strcpy (p1, p2 );

Cout <"after copying p1 becomes"
<P1 <endl;

}

Return 0;
}
/*
HelloWorld
MyGirl
10
6
-5
After copying p1 becomes myGirl

Abcdef
Bcdefg
6
6
-1
After copying p1 becomes bcdefg

Abcdefg
... The remaining full text>

Compile a function to convert an integer to a numeric string. C Language

# Include <stdio. h> # define N 10
// Compile a function to extract the numbers of All integers and convert them into numeric strings,
// Output the string in the main function. Use a simple C language without a pointer.
Int main ()
{
Int number_int, I, str_len;
Char number_str [N], swap_temp;
Scanf ("% d", & number_int );
I = 0;
While (number_int)
{
Number_str [I] = number_int % 10 + 48;
Number_int/= 10;
I ++;
}
Number_str [I] = '\ 0 ';
Str_len = I-1;
For (I = 0; I <= str_len/2; I ++)
{
Swap_temp = number_str [I];
Number_str [I] = number_str [str_len-i];
Number_str [str_len-i] = swap_temp;
}
Printf ("% s \ n", number_str );

}