A JS question about reference passing and value passing

First look at question 1

var obj = {name: ' A '}function  Bar (obj) {    console.log (obj.name);     = {Name: "B"};    Console.log (obj.name)}console.log (bar (obj)) console.log (obj.name)

In the chrome console, do the following to find out what to print

a b a

Question 2, a little bit of a change

var obj = {name: ' A '}function  Bar (obj) {    console.log (obj.name);     = "B";    Console.log (obj.name)}console.log (bar (obj)) console.log (obj.name)

In the chrome console, do the following to find out what to print

Abb

Question 3, change it a little bit.

var obj = {name: ' A '}function  Bar (obj) {    console.log (obj.name);     var obj = {name: "B"};    Console.log (obj.name)}console.log (bar (obj)) console.log (obj.name)

In the chrome console, do the following to find out what to print

Aba

Question 4, continue to change

var obj = "name"function  Bar (obj) {    console.log (obj);     var obj = "age";    Console.log (obj)}console.log ("Bar (obj)") console.log (obj )

Find this to print

Nameagename

Question 5, continue to change

var obj = "name"function  Bar () {    console.log (obj);     var obj = "age";    Console.log (obj)}console.log ("Bar (obj)") console.log (obj )

Discover Print in sequence

Undefinedagename

Question 6, or continue to change

var obj = "name"function  Bar () {    console.log (obj);      = "Age";    Console.log (obj)}console.log ("Bar (obj)") console.log (obj )

Look what you're going to print this time.

Nameageage

If you're right, you understand reference passing and value passing, understanding local variables and global variables, and if you're wrong, think about it.

A JS question about reference passing and value passing