A problem that makes people want to break their heads.

A problem that makes people want to break their heads.
$numo = "";
(($bqno%1==0) $numo ==1: ($bqno%2==0))? $numo ==2: ($bqno%3==0))? $numo ==3:false;
Echo $numo;
With a three-mesh operation, repeated checks, no grammatical errors, but why can not be called out?
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You have other places of assignment besides $numo= "";
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First of all, your assignment to $numo is only the first sentence of $numo= '; $numo of course is empty ah;
The trinocular operator does not assign the result to any variable here. It doesn't really matter what the output is.
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Because there is no assignment at all in your code
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The landlord's temper is too big. Let's say I replied. Don't scold me.
You're not going to have a result.
Let's take a look at this $bquno%1==0, this is true. Then this lump, three wood operation, Operation finished, but with $numo no relationship ah, no assignment, is wrong, looked at, understand the $bqno and $numo relationship.
The summary is that there is no assignment to $numo at all.
After not reply. So goodbye

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