About the PHP loop output solution

About PHP Loop output

PHP Code

  
   $list = "", if (! $car [' name ']) {    $list = ' without any information! ';} else{    $i =1;    foreach ($car [' name '] as $nm) {    $list. = '    . $nm [' XM ']. '    ;  $i + +;    }} Print_r ($list);

The above code output data: Li Qiang, Li Qiang, Li Qiang, Hong Fei
Whether it can achieve the results of the judgment output if "Li Qiang" repeat, then forced renamed to Li Qiang 1, Li Qiang 2, Li Qiang 2, Hong Fei?

------Solution--------------------
Count Yes

PHP Code

$car [' name '] = Array (' xm ' = ' li Qiang '), Array (' xm ' = ' li Qiang '), Array (' xm ' = ' li Qiang '), Array (' xm ' = ' Feihong '),) $list = "", if (! $car [' name ']) {$list = ' no information! ';}    else{$i = 1;    $buf = Array ();      foreach ($car [' name '] as $NM) {if (! isset ($buf [$nm [' XM ']]) $buf [$nm [' xm ']] = '; $list. = "\ n". $nm [' XM ']. ($buf [$nm [' XM ']]++].      "\ n";    $i + +; }}print_r ($list);
------Solution--------------------

  
  

   
   

     PHP code 
    
 $list = ""; $car = Array (' name ' =>array (' 0=>array ' (' xm ' = ' liming '), 1=>array (' xm ' = ' Bill '), 2=>array (' xm ' = ')    Bill '), 3=>array (' xm ' = ' bill '));    if (! $car [' name ']) {$list = ' nothing ';        }else{$i = 1;                foreach ($car [' name '] as $NM) {if (Strstr ($list, $nm [' XM ']) && $i = = 1) {                $list = Str_replace ($nm [' XM '], $nm [' XM ']. $i, $list); $list. = $nm [' XM '].                ($i + 1);            $i + +; }else{if (strstr ($list, $nm [' XM '])) {$list. = $nm [' XM '].                    $i + 1);                $i + +;                }else{$list. = $nm [' XM ']; }}}} Print_r ($list); 
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