After Json_encode, the JSON data becomes [{"A", "1"}], how to change to {"A", "1"}

function Get_js_array ($sql) {$result = mysql_query ($sql); $arr = Array (); while ($row = Mysql_fetch_array ($result, Mysql_ ASSOC) {$arr [] = $row;  } $js = Json_encode ($arr); Mysql_free_result ($result); Mysql_close ($conn); return $js;}

Please rewrite it according to this. Thank you

Reply to discussion (solution)

$js = Json_encode (Array_pop ($arr));

$js = Json_encode (Array_pop ($arr));

That is true. The output I want is a {"A", "1"},{"B", "1"};

I now output this method is [{"A", "1"},{"B", "1"}]

After you modify this method output is {"A", "1"}

The brackets were removed. But only one piece of data is output.

After Json_encode, the JSON data becomes [{"A", "1"}], how to change to {"A", "1"}

Yours?? Is??? Of

$js = Trim (Json_encode ($arr), ' [] ');

Your demand is strange, it was an array, but not an array representation.

$js = Trim (Json_encode ($arr), ' [] ');

Your demand is strange, it was an array, but not an array representation.

I do the background interface for iOS. They can't parse the json_encode after they pass through. They can only parse {"A", "1"} ... Add [] They can't parse it.

Thank you, sir. OK..

You?? Element, no?? What's the line?
You json_encode first, and then? Off?? But how do you decode?

