C language "all-around comparison function" (second edition), any data type

First version:
[Cpp]
# Include <stdio. h>
 
// The following is the all-round comparison function. a> B returns an integer. a <B returns a negative number. a = B returns 0.
# Define COMPARE (TYPE, a, B) (TYPE) a-(TYPE) B)
 
Int main (int argc, char * argv [])
{
Double a = 1, B = 1.5, c;
Int x = 10, y = 1, z;
Char m = 'M', n = 'n', k;

C = COMPARE (double, a, B );
Printf ("% lf \ n", c );

Z = COMPARE (int, x, y );
Printf ("% d \ n", z );

K = COMPARE (char, m, n );
Printf ("% d \ n", k );

Return 0;
}

The returned data types are inconsistent, which is related to the input data type. Can we return the int type results uniformly?

Version 2: The comparison result is of the int type.

[Cpp]
# Include <stdio. h>
 
// The following is the all-round comparison function. a> B returns an integer. a <B returns a negative number. a = B returns 0.
# Define COMPARE (TYPE, a, B) (TYPE) a-(TYPE) B) = 0? 0 :( (TYPE) a-(TYPE) B)> 0? 1:-1 ))
 
Int main (int argc, char * argv [])
{
Int result;
Double a = 1, B = 1.5;
Int x = 10, y = 1;
Char m = 'M', n = 'n ';
Float f1 = 6.02, f2 = 6.0200002;

Result = COMPARE (double, a, B );
Printf ("% d \ n", result );

Result = COMPARE (int, x, y );
Printf ("% d \ n", result );

Result = COMPARE (char, m, n );
Printf ("% d \ n", result );

Result = COMPARE (float, f1, f2 );
Printf ("% d \ n", result );

Return 0;
}