C language --- simple date plus 1 day System

 

If you want to take the exam, write it. If you have the same requirements, take it away.

 

 

# Include <stdio. h>

 

 

Void main () // defines some date functions

 

 

{

Char tmps;

Do

{

Printf ("enter a date (year month day )");

 

 

Int year, month, day, tmp;

 

 

Scanf ("% d", & year, & month, & day );

 

 

If (year <1000 | year> 9999) // determines the year.

{

 

 

Printf ("the year is incorrect. Please enter a four-digit positive integer ");

 

 

}

Else if (month> 12 | month <1) // you can specify a month.

{

 

 

Printf ("incorrect monthly input, please enter a positive integer between 1 and 12 ");

 

 

}

Else

{

 

 

Switch (month) // defines the number of days per month

{

 

 

Case 1:

Tmp = 31;

Break;

 

 

Case 2:

Tmp = 28;

Break;

 

 

Case 3:

Tmp = 31;

Break;

 

 

Case 4:

Tmp = 30;

Break;

 

 

Case 5:

Tmp = 31;

Break;

Case 6:

Tmp = 30;

Break;

 

 

Case 7:

Tmp = 31;

Break;

 

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Case 8:

Tmp = 31;

Break;

 

 

Case 9:

Tmp = 30;

Break;

 

 

Case 10:

Tmp = 31;

Break;

 

 

Case 11:

Tmp = 30;

Break;

 

 

Case 12:

Tmp = 31;

Break;

 

 

}

 

 

If (day = tmp) // determines whether it is the last day

{

Printf ("the date of the next day is % d 1 \ n", year, month + 1 );

}

Else if (day = tmp & month = 12) // determines whether it is the last day of the last month.

{

Printf ("the date of the next day is % d 1 1 \ n", year + 1 );

}

Else

{

Printf ("the date of the next day is % d \ n", year, month, day + 1 );

}

}

Printf ("continue? (Y/n )");

Scanf ("% s", & tmps );

 

 

} While (tmps = 'y ');

 

 

 

 

}

From: Str1ven's Blog