Codeforces Round #204 (Div. 1) A. Jeff and Rounding

Source: Internet
Author: User
Tags integer numbers

A. Jeff and Roundingtime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard output

Real numbers, Bytes,A, Please..., please ,...,ANAs a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes nOperations, each of them goes as follows:

    And jI  = J) That haven'tbeen chosen yet;
  • ITo the nearest integer that isn' t more thanI(Assign toI:IToken ⌋);
  • JTo the nearest integer that isn' t less thanJ(Assign toJ:JToken ⌉).

Input

NMemory ≤ memory 2000). The next line contains nReal numbers,,NAILimit ≤limit 10000), given with exactly three digits after the decimal point. The numbers are separated by spaces.

Output

Sample test (s) input

Output
Input
Output
Note

Priority = Priority 1, priority,JGeneration = Generation 4), ILimit = Limit 2, limit,JOutputs = outputs 3), ILimit = limit 5, limit,JLatency = Limit 6). In this case, the difference will equal.

#include <stdio.h>#include <iostream>#include <math.h>#include <string.h>using namespace std;int main (){    int n,s1,s2,i;    while(scanf("%d",&n)!=EOF){        double sum,x;        for(i=0,s1=0,s2=0,sum=0;i<n+n;i++){            scanf("%lf",&x);            int temp=(int)x;            x=x-(double)temp;            if(x!=0)            sum+=x,s1++;            else s2++;        }        int k=min(s1,n);        double ans=100000000.0;        for(i=0;i<=k;i++){            if(i+s2>=n){            ans=min(ans,fabs(sum-i*1.0));            }        }        printf("%.3f\n",ans);    }    return 0;}


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