760. Find Anagram Mappings Lookup mappings

Given lists A B and, and is a anagram of. is an B anagram of means are made by A B A B Rand Omizing the order of the elements in A .

We want to find a index mapping P , from A to B . A mapping P[i] = j means the i th element in A appears with at B index j .

These lists and may A B contain duplicates. If There is multiple answers, output any of them.

For example, given

A = [50, 12, 32, 46, 28], 50]b = [+]

We should return

[1, 4, 3, 2, 0]

As P[0] = 1Because the 0th element of AAppears at B[1], and P[1] = 4Because the 1St element of AAppears at B[4], and so on.

Note:

1. A, Bhas equal lengths in range [1, 100] .
2. A[i], B[i]is integers in range [0, 10^5] .

Given the list of two A and B, B is an alphabetic group of a. B is an alphabetic group of a, which means that B is made by randomization of the order of elements in a.
We want to find an index map from a to B p. map p [i] = J means that the I element in a appears in B with index J.
These lists A and B may contain duplicates. If there are multiple answers, either of them is output.

  
 

   
  

  
/**
   
  

  
 * @param {number[]} A
   
  

  
 * @param {number[]} B
   
  

  
 * @return {number[]}
   
  

  
 */
   
  

  
var anagramMappings = function (A, B) {
   
  

  
 let res = [];
   
  

  
 res.length = A.length;
   
  

  
 let m = {};
   
  

  
 for (let i = 0; i < B.length; i++) {
   
  

  
 m[B[i]] = i;
   
  

  
 }
   
  

  
 for (let i in A) {
   
  

  
 res[i] = m[A[i]];
   
  

  
 }
   
  

  
 return res;
   
  

  
};
   
  

  

   
  

  
let A  =    [ 12  ,    28     46     32     50  ;   
   
  

  
let B = [50, 12, 32, 46, 28];
   
  

  
let res = anagramMappings(A, B);
   
  

  
console.log(res);
  
 

From for notes (Wiz)

760. Find Anagram Mappings Lookup mappings