Alert generates the random value code in the array, and the alert array value code

Alert generates the random value code in the array, and the alert array value code

Js Code

/** Then alert returns the array value * a, indicating the array */function alert1 (a) {var alength =. length; if (alength> 1) {var r = random1 (0, alength); alert (a [r]); a [r] =-1; var temp = Array (alength-1); var t = false; for (var I = 0; I <. length; I ++) {if (I = r) {t = true;} else {if (t = false) {temp [I] = a [I];} else {temp [I-1] = a [I] ;}} alert1 (temp );} else {alert (a [0]) ;}}

Js Code

/*** The value between min (inclusive) and max (excluded) */function random1 (min, max) {return Math. floor (min + (Math. random () * 10) % (max-min )));}

For js to loop out a set of data and assign it to an array, the last alert will output an array problem. The code for the array loop is as follows:

Var arr = new array ();
Changed:
Var arr = new Array ();

How does js determine whether a value is the first element in the array and generate the value alert. It is not a printing element, but a printing element.

<Script type = "text/javascript">
Function aa (){
Var mycars = new Array ();
Mycars [0] = "aaa ";
Mycars [1] = "bbb ";
Mycars [2] = "ccc ";
// Ie does not support the indexOf method. The following if code is compatible with ie.
If (! Array. indexOf ){
Array. prototype. indexOf = function (obj ){
For (var I = 0; I <this. length; I ++ ){
If (this [I] = obj ){
Return I;
}
}
Return-1;
}
}
Var a = mycars. indexOf ('bbb ');
// The array starts from 0, so the element position is equal to the return value + 1. If it is too troublesome, use var a = mycars. indexOf ('bbb ') + 1; then the returned value is its position.
Alert ();
}
Window. onload = aa;
</Script>
Try it !!!