Golang Advanced (v) JSON processing for--restful development

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Objective

RESTful development, object to Json,json to the object is very frequent operation, how to less repetitive code, for this purpose to open this article

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Simplifying data structures

Each time you need to return the data have code,msg,data these fields, each type of these fields is too complicated, there is interface way to replace any type, and then use when the data field and any other type of combination

package modeltypestruct {    string      `json:"code"`    Msg  string      `json:"msg,omitempty"`    interface`json:"data,omitempty"`}typestruct {    string`json:"username"`    string`json:"password,omitempty"`}

JSON and HTTP requests together

The JSON-processing wrapper for Golang, which allows the object to be read directly from the HTTP request, outputting the object in JSON format to the response

 PackageToolsImport("bytes"    "Encoding/json"    "FMT"    "Io/ioutil"    "Net/http")//Marshaljson put objects in JSON format in responsefuncMarshaljson (w http. Responsewriter, VInterface{}) error {data, err: = json. Marshal (v)ifErr! =Nil{returnERR} FMT. Fprint (W,string(data))return Nil}//Unmarshaljson Remove object from RequestfuncUnmarshaljson (req *http. Request, VInterface{}) Error {result, err: = Ioutil. ReadAll (req. Body)ifErr! =Nil{returnERR} JSON. Unmarshal ([]byte(bytes. Newbuffer (Result). String ()), V)return Nil}

Call

After the above processing, the call becomes quite easy, does not need to do more repetition coding, the code readability greatly improves

func UserLoginndler(w http.ResponseWriter, r *http.Request) {    user := &model.User{}    tools.UnMarshalJson(r, user)    "1001""账号或者密码错误"}    if"sweetop""123456" {        "0""success"}    }    tools.MarshalJson(w, resp)}

func UserListHandler(w http.ResponseWriter, r *http.Request) {    "0""success"}    make([]model.User, 0)    append"sweetop"})    tools.MarshalJson(w, resp)}