Linux controls the sequence of startup of two programs
Source: Internet
Author: User
Linux controls the order in which two programs are started: service1 and service2. service2 depends on service1, that is, it can be started only after service1 is started. if the service1 application occupies a specified tcp port, the following script can perform this operation: echo & quot; service1start... & quot ;...
Linux controls the order in which two programs are started: service1 and service2. service2 depends on service1, that is, it can be started only after service1 is started. if the service1 application occupies a specified tcp port, the following script can perform this operation: echo "service1 start... ". /service1.sh www.2cto.com netstat-tlnp | grep 2098 until ["$? "-Eq" 0 "] do echo" waiting service1 to startup... "sleep 1 www.2cto.com netstat-tlnp | grep 2098 done echo" service1 started. ". /service2.sh echo "service2 started. "2098 indicates the tcp port occupied by service1.
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