Upload Image:
Copy the Code code as follows:
if (!empty ($_files["img" ["name"])) {//Extract the File field content name and determine
$path = "uppic/"; Upload path
if (!file_exists ($path))
{
Check if there is a folder, if not created, and give the highest permissions
mkdir ("$path", 0700);
}//end IF
Allow upload of file formats
$TP = Array ("Image/gif", "Image/pjpeg", "image/jpeg");
Check if the upload file is in a type that allows uploading
if (!in_array ($_files["img" ["type"], $TP))
{
echo "";
Exit
}//end IF
$filetype = $_files[' img ' [' type '];
if ($filetype = = ' Image/jpeg ') {
$type = '. jpg ';
}
if ($filetype = = ' Image/jpg ') {
$type = '. jpg ';
}
if ($filetype = = ' Image/pjpeg ') {
$type = '. jpg ';
}
if ($filetype = = ' Image/gif ') {
$type = '. gif ';
}
if ($_files["img" ["Name"])
{
$today =date ("Ymdhis"); Get time and assign a value to a variable
$file 2 = $path. $today. $type; The full path of the picture
$img = $today. $type; Picture name
$flag = 1;
}//end IF
if ($flag) $result =move_uploaded_file ($_files["img" ["Tmp_name"], $file 2);
Note that the first parameter passed to Move_uploaded_file here is a temporary file uploaded to the server
}//end IF
The value of $img is then written to the corresponding field in the database
To delete a picture:
Copy the Code code as follows:
Unlink ("uppic/". $img); Of course, the value of the variable is read from the database, PHP deleted pictures more concise than the ASP
The above describes the simple PHP upload image, delete the image implementation code, including the content, I hope the PHP tutorial interested in a friend helpful.