What do you need to be aware of in PHP writing API?

First Write API program, using native PHP, no restful requirements. If you only implement functionality to return JSON data, it feels easy to implement most of the functionality, so what do you need to be aware of in addition to functional implementation? Novice seeking guidance. Already posted code altogether 4 files

  
    $code,            'message' => $message,            'data' => $data        );                echo json_encode($result);    }}

!--? php/* * Singleton mode database connection */require_once (' response.php '); class Db {static private $_instance; static private $_connectsource; Private $_dbconfig = Array (' host ' =--> ' localhost ', ' user ' = ' root ', ' password ' = ' xxx ', ' Database ' = ' sportsstore '); Private Function __construct () {} static public function Getinstace () {if (! ( Self::$_instance instanceof Self)} {self::$_instance = new self (); } return self::$_instance; Public Function Connect () {if (!self::$_connectsource) {Self::$_connectsource = Mysqli_c Onnect ($this->_dbconfig[' host '), $this->_dbconfig[' user ', $this->_dbconfig[' password '], $this ->_dbconfig[' database '); if (!self::$_connectsource) {throw new Exception ("MySQL connect error". Mysql_errno ()); }} return Self::$_connectsource; }}

This is the login code.

/**login.phh 登录接口*/
  
   connect();} catch (Exception $ex) {    return Response::show(402,"数据库连接失败");}$account = mysqli_real_escape_string($link, trim($_POST['account']));$password = mysqli_real_escape_string($link, trim($_POST['password']));$query = "select * from users where account = \"$account\"";$result = mysqli_query($link, $query);if(mysqli_num_rows($result)==1){    $row = mysqli_fetch_array($result);    if($row['password'] == $password){        return Response::show(200, '登录成功');    }else{        return Response::show(202,'密码不正确');    }}else{    return Response::show(201,'账户不存在');}

/**getPersonalInfo.phh 查询个人信息接口*/
  
   connect();} catch (Exception $ex) {    return Response::show(402,'数据库连接失败');}$account = isset($_GET['account']) ? mysqli_real_escape_string($link, trim($_GET['account'])) : null;if($account === null){    return Response::show(401,'未登录');}$query = "select * from users where account=\"$account\"";$result = mysqli_query($link, $query);$row = mysqli_fetch_assoc($result);return Response::show(200,"操作成功",$row);

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First Write API program, using native PHP, no restful requirements. If you only implement functionality to return JSON data, it feels easy to implement most of the functionality, so what do you need to be aware of in addition to functional implementation? Novice seeking guidance. Already posted code altogether 4 files

 !--? phpclass Response {/** * Output the communication data in JSON * @param integer $cod E Status code * @param string $message message * @param array $data data */public static function show ($code, $message =        ", $data = Array ()) {if (!is_numeric ($code)) {return '; } $result = Array (' Code ' =--> $code, ' message ' = = $message, ' data ' =&G T                $DATA);    echo Json_encode ($result); }}

!--? php/* * Singleton mode database connection */require_once (' response.php '); class Db {static private $_instance; static private $_connectsource; Private $_dbconfig = Array (' host ' =--> ' localhost ', ' user ' = ' root ', ' password ' = ' xxx ', ' Database ' = ' sportsstore '); Private Function __construct () {} static public function Getinstace () {if (! ( Self::$_instance instanceof Self)} {self::$_instance = new self (); } return self::$_instance; Public Function Connect () {if (!self::$_connectsource) {Self::$_connectsource = Mysqli_c Onnect ($this->_dbconfig[' host '), $this->_dbconfig[' user ', $this->_dbconfig[' password '], $this ->_dbconfig[' database '); if (!self::$_connectsource) {throw new Exception ("MySQL connect error". Mysql_errno ()); }} return Self::$_connectsource; }}

This is the login code.

/**login.phh 登录接口*/
  
   connect();} catch (Exception $ex) {    return Response::show(402,"数据库连接失败");}$account = mysqli_real_escape_string($link, trim($_POST['account']));$password = mysqli_real_escape_string($link, trim($_POST['password']));$query = "select * from users where account = \"$account\"";$result = mysqli_query($link, $query);if(mysqli_num_rows($result)==1){    $row = mysqli_fetch_array($result);    if($row['password'] == $password){        return Response::show(200, '登录成功');    }else{        return Response::show(202,'密码不正确');    }}else{    return Response::show(201,'账户不存在');}

/**getPersonalInfo.phh 查询个人信息接口*/
  
   connect();} catch (Exception $ex) {    return Response::show(402,'数据库连接失败');}$account = isset($_GET['account']) ? mysqli_real_escape_string($link, trim($_GET['account'])) : null;if($account === null){    return Response::show(401,'未登录');}$query = "select * from users where account=\"$account\"";$result = mysqli_query($link, $query);$row = mysqli_fetch_assoc($result);return Response::show(200,"操作成功",$row);

Update

• Data integrity

• Semantic simplicity

• Version controllable

• Flexible response

• Safe and reliable (https can be considered, token mechanism, IP whitelist, etc.)

• Response speed

• Uniform style (don't go out, return to the same format)

Remember, don't write Json_ecode ($array); exit; Such code is good.
With your own lightweight like apirespnse ($data), though you only return JSON.

The upstairs is good, I add one more.
Uniform format

For example, the returned data must have a uniform name of the "Request status results", such as the returned data must be uniformly placed in a variable.
Avoid the presence of different places in the foreground to judge different names.

Registered interface and draw the interface must be secure to prevent malicious brush!!!

You put your code on first. I'll learn a bit too.

