Accuracy problem in JS floating point operation

Remember in a project, the use of JS for a series of arithmetic operations, the calculation will have floating-point type, the simple calculation, and finally in the test process, the supervisor in the verification of the data when the results of the calculation is a problem, and then very puzzled, found in the Internet search answer,http/ www.css88.com/archives/7340

Cause: The decimal number in the calculation is converted to binary, calculated, and the result is converted to decimal (often some floating-point type values are converted to binary is infinite), so it can often lead to precision problems

So how to solve it?

The following options are available online:

1 /**2 * * Additive function for accurate addition results3 * * Description: JavaScript addition results will be error, when the two floating-point number added will be more obvious. This function returns a more accurate addition result. 4 * * Call: Accadd (ARG1,ARG2)5 * * return value: Arg1 plus arg2 accurate results6  **/7 functionAccadd (arg1, arg2) {8     varR1, R2, M, C;9     Try {TenR1 = Arg1.tostring (). Split (".") [1].length; One     } A     Catch(e) { -R1 = 0; -     } the     Try { -r2 = arg2.tostring (). Split (".") [1].length; -     } -     Catch(e) { +r2 = 0; -     } +c = Math.Abs (R1-r2); Am = Math.pow (10, Math.max (R1, r2)); at     if(C > 0) { -         varCM = Math.pow (10, c); -         if(R1 >R2) { -Arg1 = number (arg1.tostring (). Replace (".", "")); -arg2 = number (arg2.tostring (). Replace (".", "")) *cm; -}Else { inArg1 = number (arg1.tostring (). Replace (".", "")) *cm; -arg2 = number (arg2.tostring (). Replace (".", "")); to         } +}Else { -Arg1 = number (arg1.tostring (). Replace (".", "")); thearg2 = number (arg2.tostring (). Replace (".", "")); *     } $     return(Arg1 + arg2)/m;Panax Notoginseng } -   the //Adding an Add method to the number type makes it more convenient to call.  +Number.prototype.add =function(ARG) { A     returnAccadd (ARG, This); the }; +  - /** $ * * Subtraction function to get accurate subtraction results $ * * Description: JavaScript subtraction results will be error, when the two floating-point subtraction will be more obvious. This function returns a more accurate subtraction result.  - * * Call: Accsub (ARG1,ARG2) - * * return value: Arg1 plus arg2 accurate results the  **/ - functionaccsub (arg1, arg2) {Wuyi     varR1, R2, M, N; the     Try { -R1 = Arg1.tostring (). Split (".") [1].length; Wu     } -     Catch(e) { AboutR1 = 0; $     } -     Try { -r2 = arg2.tostring (). Split (".") [1].length; -     } A     Catch(e) { +r2 = 0; the     } -m = Math.pow (Ten, Math.max (R1, r2));//Last Modify by Deeka//dynamic control accuracy length $n = (r1 >= r2)?r1:r2; the     return((ARG1 * M-ARG2 * m)/m). toFixed (n); the } the   the //Adding a Mul method to the number type makes it more convenient to call.  -Number.prototype.sub =function(ARG) { in     returnAccmul (ARG, This); the }; the  About  the /** the * * Multiplication function to get accurate multiplication results the * * Note: The multiplication result of JavaScript will be error, it will be more obvious when two floating-point numbers are multiplied. This function returns a more accurate multiplication result.  + * * Call: Accmul (ARG1,ARG2) - * * return value: Arg1 times the exact result of Arg2 the  **/Bayi functionAccmul (arg1, arg2) { the     varm = 0, S1 = arg1.tostring (), S2 =arg2.tostring (); the     Try { -M + = S1.split (".") [1].length; -     } the     Catch(e) { the     } the     Try { theM + = S2.split (".") [1].length; -     } the     Catch(e) { the     } the     returnNumber (S1.replace (".", "")) * Number (S2.replace (".", ""))/Math.pow (10, m);94 } the   the //Adding a Mul method to the number type makes it more convenient to call.  theNumber.prototype.mul =function(ARG) {98     returnAccmul (ARG, This); About }; - 101 102 /** 103 * * Division function to get accurate division results104 * * Description: JavaScript division results will be error, when the two floating point number is more obvious when dividing. This function returns a more accurate division result.  the * * Call: Accdiv (ARG1,ARG2)106 * * return value: Arg1 divided by the exact result of Arg2107  **/108 functionAccdiv (arg1, arg2) {109     varT1 = 0, t2 = 0, R1, R2; the     Try {111T1 = arg1.tostring (). Split (".") [1].length; the     }113     Catch(e) { the     } the     Try { theT2 = arg2.tostring (). Split (".") [1].length;117     }118     Catch(e) {119     } -      with(Math) {121R1 = number (arg1.tostring (). Replace (".", ""));122r2 = number (arg2.tostring (). Replace (".", ""));123         return(R1/R2) * POW (T2-t1);124     } the }126  127 //Adding a Div method to the number type makes it easier to call.  -Number.prototype.div =function(ARG) {129     returnAccdiv ( This, ARG); the};

Accuracy problem in JS floating point operation