Hdu3452 remove the smallest edge set from the undirected tree so that any leaf is not connected to the root/min cut, and hdu3452 is connected.

Source: Internet
Author: User

Hdu3452 remove the smallest edge set from the undirected tree so that any leaf is not connected to the root/min cut, and hdu3452 is connected.

The idea is coming up. The leaf connects to the edge of the sink node. inf ensures that the edge will not be cut, and the root node can be cut to the sink node. Pay attention to the bidirectional Edge building of the undirected tree. Basic questions, in minutes 1A:

#include<iostream>#include<queue>#include<cstdio>#include<cstring>#include<set>#include<vector>using namespace std;const int inf=0x3f3f3f3f;const int maxv=1005,maxe=10000;int nume=0;int head[maxv];int e[maxe][3];void inline adde(int i,int j,int c){    e[nume][0]=j;e[nume][1]=head[i];head[i]=nume;    e[nume++][2]=c;    e[nume][0]=i;e[nume][1]=head[j];head[j]=nume;    e[nume++][2]=0;}int ss,tt,n,m;int vis[maxv];int lev[maxv];bool bfs(){    for(int i=0;i<maxv;i++)      vis[i]=lev[i]=0;    queue<int>q;    q.push(ss);    vis[ss]=1;    while(!q.empty())    {        int cur=q.front();        q.pop();        for(int i=head[cur];i!=-1;i=e[i][1])        {            int v=e[i][0];            if(!vis[v]&&e[i][2]>0)            {                lev[v]=lev[cur]+1;                vis[v]=1;                q.push(v);            }        }    }    return vis[tt];}int dfs(int u,int minf){    if(u==tt||minf==0)return minf;    int sumf=0,f;    for(int i=head[u];i!=-1&&minf;i=e[i][1])    {        int v=e[i][0];        if(lev[v]==lev[u]+1&&e[i][2]>0)        {            f=dfs(v,minf<e[i][2]?minf:e[i][2]);            e[i][2]-=f;e[i^1][2]+=f;            sumf+=f;minf-=f;        }    }    if(!sumf) lev[u]=-1;    return sumf;}int dinic(){    int sum=0;    while(bfs())sum+=dfs(ss,inf);    return sum;};int ind[maxv];void read_build(){    int aa,bb,cc;    for(int i=0;i<n-1;i++)     {        scanf("%d%d%d",&aa,&bb,&cc);        adde(aa,bb,cc);        adde(bb,aa,cc);        ind[aa]++;ind[bb]++;     }     for(int i=1;i<=n;i++)        if(i!=m&&ind[i]==1)        {            adde(i,tt,inf);        }  /*  for(int i=0;i<=tt;i++)      for(int j=head[i];j!=-1;j=e[j][1])      {          if(j%2==0)          printf("%d->%d:%d\n",i,e[j][0],e[j][2]);      }*/}void init(){    nume=0;    ss=m;tt=n+1;    for(int i=0;i<=tt;i++)      {          head[i]=-1;ind[i]=0;      }}int main(){      while(~scanf("%d%d",&n,&m)&&(n||m))     {         init();        read_build();       int ans;       ans=dinic();      printf("%d\n",ans);    }    return 0;}






Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.