How do I list the time array together?

Source: Internet
Author: User
Array results after the database has been printed:

Array(    [0] => Array        (            [department] => 雅典娜              [sign] => 0            [time] => 2015年06月01日            [surname] => 星史        )    [1] => Array        (            [department] => 雅典娜            [sign] => 0            [time] => 2015年06月02日            [surname] =>  星史        )    [2] => Array        (            [department] => 雅典娜            [sign] => 0            [time] => 2015年06月03日            [surname] => 瞬        )    [3] => Array        (            [department] => 雅典娜            [sign] => 0            [time] => 2015年06月03日            [surname] => 紫龙        )

I want to count the same array, for example, there are two arrays of star history, statistics are 2, others are 1.
Then the array notation is

$array=array();foreach($上面打印的数组 as $v){    if(!isset($array[$v['surname']])){              $out_put[$v['surname']]['time']=$v['time'];              $array[$v['surname']]['count']=1;    }else{         $array[$v['surname']]['count']=$array[$v['surname']]['count']+1;    }}

And then print out

Array(    [星史] => Array        (           //问题再这里,如何数组输出多个时间呢  [time] = 2015年06月01日、2015年06月02日             [time] =2015年06月01日;            [count] => 2        )    [瞬] => Array        (             [time] =2015年06月03日;             [count] => 1        )    [紫龙 => Array        (           [time] =2015年06月03日;            [count] => 1        ))

How does this print output time?

Reply content:

Array results after the database has been printed:

Array(    [0] => Array        (            [department] => 雅典娜              [sign] => 0            [time] => 2015年06月01日            [surname] => 星史        )    [1] => Array        (            [department] => 雅典娜            [sign] => 0            [time] => 2015年06月02日            [surname] =>  星史        )    [2] => Array        (            [department] => 雅典娜            [sign] => 0            [time] => 2015年06月03日            [surname] => 瞬        )    [3] => Array        (            [department] => 雅典娜            [sign] => 0            [time] => 2015年06月03日            [surname] => 紫龙        )

I want to count the same array, for example, there are two arrays of star history, statistics are 2, others are 1.
Then the array notation is

$array=array();foreach($上面打印的数组 as $v){    if(!isset($array[$v['surname']])){              $out_put[$v['surname']]['time']=$v['time'];              $array[$v['surname']]['count']=1;    }else{         $array[$v['surname']]['count']=$array[$v['surname']]['count']+1;    }}

And then print out

Array(    [星史] => Array        (           //问题再这里,如何数组输出多个时间呢  [time] = 2015年06月01日、2015年06月02日             [time] =2015年06月01日;            [count] => 2        )    [瞬] => Array        (             [time] =2015年06月03日;             [count] => 1        )    [紫龙 => Array        (           [time] =2015年06月03日;            [count] => 1        ))

How does this print output time?

php
$arr = Array (' department ' + = ' Athena ', ' sign ' = + 0, ' time ' = ' June 01, 2015 ', ' surname ' = ' star history ', Array (' Department ' = ' Athena '), ' Sign ' = 0, ' time ' = ' June 02, 2015 ', ' surname ' + ' star history ', Array ( ' Department ' = ' Athena ', ' sign ' + 0, ' time ' = ' June 03, 2015 ', ' surname ' =& Gt ' instantaneous '), Array (' Department ' = ' Athena ', ' sign ' = + 0, ' time ' = ' June 03, 2015 ', ' surname ' + ' Violet Dragon '); $array =array (); foreach ($arr as $v) {if (!isset ($array [$v [' Surnam E ']]) {$array [$v [' Surname ']][' count ']=1; $array [$v [' Surname ']][' time ']= $v [' time ']; }else{$array [$v [' Surname ']][' count ']+=1; $array [$v [' Surname ']][' time '].= ', '. $v [' time ']; }}print_r ($array); Uasort ($array, function ($a, $b) {return $b [' count ']-$a [' count '];});
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