How does a regular match consecutive numbers?

Source: Internet
Author: User
Regular numbers

① $number = 1234784;
The regular matching result is: 1234

② $number = 389456723;
The regular matching result is: 4567


Reply to discussion (solution)

No sequential numbers can be matched only with regular

No sequential numbers can be matched only with regular
What solution should be used?

Is the first 78 not a continuous one? is the second 89 and 23 not a continuous one? Why not?

Does "386387" count as continuous? Do you want to match?

① $number = 1234784;
The regular matching result is: 1234

② $number = 389456723;
The regular matching result is: 4567

It seems to match 4 consecutive bits, if so, it's just a few things:

$s = 389456723;

4 consecutive Bits
$r = ' (1234|2345|3456|4567|5678|6789) ';
Preg_match_all ('/'. $r. '/', $s, $m);

Print_r ($m [0]);


Over 3 consecutive positions
$r = ' (1234|2345|3456|4567|5678|6789|123|234|345|456|567|678|789) ';
Preg_match_all ('/'. $r. '/', $s, $m);

Print_r ($m [0]);

2 or more, you don't have to demonstrate.

It seems to match 4 consecutive bits, if so, it's just a few things:

$s = 389456723;

4 consecutive Bits
$r = ' (1234|2345|3456|4567|5678|6789) ';
Preg_match_all ('/'. $r. '/', $s, $m);

Print_r ($m [0]);


Over 3 consecutive positions
$r = ' (1234|2345|3456|4567|5678|6789|123|234|345|456|567|678|789) ';
Preg_match_all ('/'. $r. '/', $s, $m);

Print_r ($m [0]);

More than 2 people do not have to demonstrate it is this! good!

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