How to replace strings in vi/vim

Source: Internet
Author: User
In vi/vim, you can use the: s command to replace the string. : S/vivian/sky/replace the first vivian in the current row with sky: s/vivian/sky/g, replace all vivian in the current row with sky: n, $ s/vivian/sky/replace the first vivian from row n to row n as sky: 2, $ s/vivian/sky/g replace row 2nd

In vi/vim, you can use the: s command to replace the string.

: S/vivian/sky/replace the first vivian in the current row with sky

: S/vivian/sky/g replace all vivian in the current row with sky

: N, $ s/vivian/sky/replace the first vivian from row n to row n as sky

: 2, $ s/vivian/sky/g to replace 2nd rows. from the beginning to the last row, all vivian values are sky.

N is a number. if n is., it indicates starting from the current row to the last row.

: % S/vivian/sky/(equivalent to: g/vivian/s // sky/) replace the first vivian of each row with sky

: % S/vivian/sky/g (equivalent to: g/vivian/s // sky/g) replace all

You can use # as the separator. The/in the middle will not be used as the separator.

: S # vivian/# sky/# replace the first vivian/in the current line with sky/

: % S +/oradata/apras/+/user01/apras1 + (replace with +/):/oradata/apras/replace with/user01/apras1/

1.: s/vivian/sky/replace the first vivian in the current row with sky

: S/vivian/sky/g replace all vivian in the current row with sky

2.: n, $ s/vivian/sky/replace the first vivian from row n to row n with sky

: N, $ s/vivian/sky/g replace all vivian values from row n to row n

(N is a number. if n is., it indicates starting from the current row to the last row)

3. replace % s/vivian/sky/(equivalent to: g/vivian/s // sky/) with the first vivian of each row as sky

: % S/vivian/sky/g (equivalent to: g/vivian/s // sky/g) replace all

4. you can use # as the separator. The/in the middle will not be used as the separator.

: S # vivian/# sky/# replace the first vivian/in the current line with sky/

5. delete ^ M from the text

Problem Description: for line breaks, use the carriage return line break (0A0D) in the window, and the carriage return (0A) in Linux. In this way, when you copy files on windows to Unix, there will always be a ^ M. please write a shell or c program that is used in unix to filter windows files (0D.

· Use the command: cat filename1 | tr-d "^ V ^ M"> newfile;

· Use the command: sed-e "s/^ V ^ M/" filename> outputfilename. Note that in methods 1 and 2, ^ V and ^ M indicate Ctrl + V and Ctrl + M. You must enter the file manually instead of pasting it.

· Processing in vi: first open the file using vi, press ESC, and then enter the command: % s/^ V ^ M //.

·: % S/^ M $/g

If the above method is useless, the correct solution is:

· Tr-d "\ r" <src> dest

· Tr-d "\ 015" dest

· Strings A> B

6. others

Use the s command to replace strings. The specific usage includes:

: S/str1/str2/use string str2 to replace str1 that appears for the first time in the line

: S/str1/str2/g replace all the str1 strings in the row with str2

:., $ S/str1/str2/g replace string str1 from the current row to the end of the body with string str2

: 1, $ s/str1/str2/g replace str1 with string str2

: G/str1/s // str2/g functions are the same as above

From the above replacement command, we can see that g is placed at the end of the command, which means to replace each appearance of the search string; without g, it means to only search

String is replaced for the first time. g is placed at the beginning of the command to replace all rows containing the search string in the body.

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