How to call JSON when the key name is a number (sample code) _php Tutorial

The value must be obtained using the obj[xx] method for characters with a key name of numeric or abnormal variables (if there are spaces).
Copy CodeThe code is as follows:

Declaring JSON data
$array = Array (' Result ' =>array ("all" = "90 queue", "status" = "success"));
$json = Json_encode ($array);

$array 1 = Array ("All" = "90 queue", "status" = "success");
$json 1 = json_encode ($array 1);
$phpjson = Json_decode ($json 1,true);//The second parameter is true, which means that the JSON data is converted to an array
When the JSON key name is a number, only the array is used to handle $phpjson[' 90 '];
?>

http://www.bkjia.com/PHPjc/825157.html www.bkjia.com true http://www.bkjia.com/PHPjc/825157.html techarticle The value must be obtained using the obj[xx] method for characters with a key name of numeric or abnormal variables (if there are spaces). Copy the code as follows:? PHP//declaration JSON Data $array = Array (' Res ...

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