How to effectively determine whether several sets of data range has the intersection

Source: Internet
Author: User
Php

5000~7000
2000~6000
8000~9000
4000~8500
5000~7000
How are these random sets of data in PHP more effective in judging if there are duplicates?

Expectations are
2000~4000
4000~5000
5000~6000
6000~7000
7000~8500
8500~9000


Reply to discussion (solution)

This post was last edited by xuzuning on 2013-10-09 09:00:13

$a = Array (array (7000), array (6000), Array (8000, 9000), Array (4000, 8500), Array (, 7000), (); $r = Arra  Y (), foreach ($a as $v) {$r [] = $v [0]; $r [] = $v [1];} $r = Array_unique ($r); sort ($r); $a = array (); for ($i =0; $i
 
  Array
  
(
[0] = = Array
(
[0] = 2000
[1] = 4000
)

[1] = = Array
(
[0] = 4000
[1] = 5000
)

[2] = = Array
(
[0] = 5000
[1] = 6000
)

[3] = = Array
(
[0] = 6000
[1] = 7000
)

[4] = = Array
(
[0] = 7000
[1] = 8000
)

[5] = = Array
(
[0] = 8000
[1] = 8500
)

[6] = = Array
(
[0] = 8500
[1] = 9000
)

)

Really very quickly, thank you moderator.

I want to get these groups of data whether there are duplicate flags,
There is a repeat return of false,
No repetition returns True,
You do not need to generate a new, non-repeating array.
Array
Array (5000, 7000),
Array (2000, 6000),
Array (8000, 9000),
Array (4000, 8500),
Array (5000, 7000),
);

The following conditions are not duplicated and expected to return true
Array
Array (2000, 3000),
Array (3000, 4000),
Array (4000, 5000)
);

 
    "Green", "B" and "Brown", "c" = "blue", "Red"); $array 2 = Array ("A" = "green", "b" = "yellow", "blue", "red") ; $result _array = Array_intersect_assoc ($array 1, $array 2);p Rint_r ($result _array);? >


Determine if the $result_array is empty

 
    "Green", "B" and "Brown", "c" = "blue", "Red"); $array 2 = Array ("A" = "green", "b" = "yellow", "blue", "red") ; $result _array = Array_intersect_assoc ($array 1, $array 2);p Rint_r ($result _array);? >


Determine if the $result_array is empty



Array_intersect_assoc
This two-dimensional array cannot be judged.
And this is a situation that does not belong to the intersection range.
Array
Array (2000, 3000),
Array (3000, 4000),
Array (4000, 5000)
);

You're not going to be a bit flexible?
If the original array is duplicated, then the resulting non-repeating array must be larger than the original array

Find out the specific scope according to the moderator's program
Alas, it is easier to simply ask for True,false:
Comparing the minimum value of any two items to the maximum of the other is the same, once there is an intersection->break loop, if until the end of the loop, there is no intersection

You're not going to be a bit flexible?
If the original array is duplicated, then the resulting non-repeating array must be larger than the original array

Thank you moderator.
Re-order the new non-repeating array,
If the number of non-repeating array elements changes, there is a overlap between the original array, right?

The flag is not likely to be correctly judged in either of the following cases
$a = Array (
Array (5000, 7000),
Array (6000, 8200),
Array (8000, 9000)
);

$a = Array (
Array (5000, 5500),
Array (6000, 6500),
Array (8000, 8500)
);

There is no more effective way.


Only need to distinguish whether it is included, can be written as function
or follow the beginning of the idea

$a = Array (7000, array (6000), Array (  8000, 9000), Array (  4000, 8500)  , Array ( 7000), Var_dump (foo ($a)); BOOL (false) $a = array (  array (7000), array (  6000, 8200),  Array (8000, 9000)), Var_dump (foo ($a)); BOOL (false) $a = array (  array (5500), Array (  6000, 6500),  Array (8000, 8500)), Var_dump (foo ($a)); BOOL (true) function foo ($a) {  $r = Array_unique (Call_user_func_array (' Array_merge ', $a));  Sort ($r);  foreach ($a as $v) {    if (array_search ($v [0], $r)! = Array_search ($v [1], $r)-1) return false;  }  return true;}

Only need to distinguish whether it is included, can be written as function
or follow the beginning of the idea

$a = Array (7000, array (6000), Array (  8000, 9000), Array (  4000, 8500)  , Array ( 7000), Var_dump (foo ($a)); BOOL (false) $a = array (  array (7000), array (  6000, 8200),  Array (8000, 9000)), Var_dump (foo ($a)); BOOL (false) $a = array (  array (5500), Array (  6000, 6500),  Array (8000, 8500)), Var_dump (foo ($a)); BOOL (true) function foo ($a) {  $r = Array_unique (Call_user_func_array (' Array_merge ', $a));  Sort ($r);  foreach ($a as $v) {    if (array_search ($v [0], $r)! = Array_search ($v [1], $r)-1) return false;  }  return true;}



This is a wonderful remark. Thank you, moderator.
Array_search ($v [0], $r)! = Array_search ($v [1], $r)-1

The above code I'll
Array
Array (2000, 3000),
Array (3000, 4000),
Array (4000, 5000)
);
The situation is considered and you can do it.
Thank you so much. M (_ _) m
  • Contact Us

    The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

    If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

    A Free Trial That Lets You Build Big!

    Start building with 50+ products and up to 12 months usage for Elastic Compute Service

    • Sales Support

      1 on 1 presale consultation

    • After-Sales Support

      24/7 Technical Support 6 Free Tickets per Quarter Faster Response

    • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.