How to obtain any xml node value using Python

How to obtain any xml node value using Python

This example describes how to obtain the value of any xml node using Python. Share it with you for your reference. The specific implementation method is as follows:

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#-*-Coding: UTF-8 -*- Import xml. dom. minidom ELEMENT_NODE = xml. dom. Node. ELEMENT_NODE Class SimpleXmlGetter (object ): Def _ init _ (self, data ): If type (data) = str: Self. root = xml. dom. minidom. parse (data) Else: Self. root = data Def _ getattr _ (self, name): # support. operation If name = 'data ': Return self. root. firstChild. data For c in self. root. childNodes: If c. nodeType = ELEMENT_NODE and c. tagName = name: Return SimpleXmlGetter (c) Def _ getitem _ (self, index): # support [] operation ENodes = [e for e in self. root. parentNode. childNodes If e. nodeType = ELEMENT_NODE and e. tagName = self. root. tagName] Return SimpleXmlGetter (eNodes [index]) Def _ call _ (self, * args, ** kwargs): # support () openration, for query conditions For e in self. root. parentNode. childNodes: If e. nodeType = ELEMENT_NODE: For key in kwargs. keys (): If e. getAttribute (key )! = Kwargs [key]: Break Else: Return SimpleXmlGetter (e) If _ name _ = "_ main __": X = SimpleXmlGetter ("sysd. xml ") Print x. sysd. sysagent. param [2]. data Print x. sysd. sysagent. param (name = "querytimeout", type = "second"). data

I hope this article will help you with Python programming.