How to obtain the complete url address and parameters in javascript

Two Methods for javascript to obtain the current URL parameter:

// Return a string parameter, for example, class_id = 3 & id = 2 & function getUrlArgStr () {var q = location. search. substr (1); var qs = q. split ('&'); var argStr = ''; if (qs) {for (var I = 0; I <qs. length; I ++) {argStr + = qs [I]. substring (0, qs [I]. indexOf ('=') + '=' + qs [I]. substring (qs [I]. indexOf ('=') + 1) + '&';} return argStr ;}

// The returned Parameter function getUrlArgObject () {var args = new Object (); var query = location. search. substring (1); // obtain the query string var pairs = query. split (","); // disconnect for (var I = 0; I <pairs. length; I ++) {var pos = pairs [I]. indexOf ('='); // find name = valueif (pos =-1) {// if not found, skip continue;} var argname = pairs [I]. substring (0, pos); // extract namevar value = pairs [I]. substring (pos + 1); // extract valueargs [argname] = unescape (value); // save as attribute} return args; // return object}

In addition, it lists some functional methods for javascript to obtain each part of the url:

Window. location. host; // return the host part of the url, for example, www.xxx.com.
Window. location. hostname; // return www.xxx.com
Window. location. href; // return the entire url string (the complete address bar in the browser), for example: www.xxx.com/index.php? Class_id = 3 & id = 2
Window. location. pathname; // return/a/index. php or/index. php
Window. location. protocol; // return the url protocol, such as http:, ftp:, maito:, and so on.
Window. location. port // The port part of the url. If the default port 80 is used, the return value is not the default port 80, but an empty character.

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