Conditional statements
delimiter \\
CREATE PROCEDURE proc_if ()
BEGIN
declare i int default 0;
if i = 1 THEN
SELECT 1;
ELSEIF i = 2 THEN
SELECT 2;
ELSE
SELECT 7;
END IF;
END\\
delimiter ;
Looping statements
While loop
delimiter \\
CREATE PROCEDURE proc_while ()
BEGIN
DECLARE num INT ;
SET num = 0 ;
WHILE num < 10 DO
SELECT
num ;
SET num = num + 1 ;
END WHILE ;
END\\
delimiter ;
Repeat cycle
复制代码
delimiter \\
CREATE PROCEDURE proc_repeat ()
BEGIN
DECLARE i INT ;
SET i = 0 ;
repeat
select i;
set i = i + 1;
until i >= 5
end repeat;
END\\
delimiter ;
Loop
复制代码
BEGIN
declare i int default 0;
loop_label: loop
set i=i+1;
if i<8 then
iterate loop_label;
end if;
if i>=10 then
leave loop_label;
end if;
select i;
end loop loop_label;
END
DISTINCT Removing duplicates
Acting on a single row
Select distinct name from A
Acting on multiple columns
Select DISTINCT name, ID from A
Count statistics
Select COUNT (distinct name) from A; --Number of name to go back in table
Distinct must be placed at the beginning
Select ID, distinct name from A; --The error will be indicated because the distinct must be placed at the beginning
Execute SQL statements Dynamically
delimiter \\
DROP PROCEDURE IF EXISTS proc_sql \\
CREATE PROCEDURE proc_sql ()
BEGIN
declare p1 int;
set p1 = 11;
set @p1 = p1;
PREPARE prod FROM ‘select * from tb2 where nid > ?‘;
EXECUTE prod USING @p1;
DEALLOCATE prepare prod;
END\\
delimiter ;
Case in SQL and then else end usage
Case has two formats. Simple case function and case search function.
--简单Case函数
CASE sex
WHEN ‘1‘ THEN ‘男‘
WHEN ‘2‘ THEN ‘女‘
ELSE ‘其他‘ END
--Case搜索函数
CASE WHEN sex = ‘1‘ THEN ‘男‘
WHEN sex = ‘2‘ THEN ‘女‘
ELSE ‘其他‘ END
In both of these ways, the same functionality can be achieved. The simple case function is relatively concise, but there are some limitations in function, such as write-judgement, compared to the search function.
There is also a problem to be aware that the case function returns only the first qualifying value, and the remaining case section is automatically ignored.
--for example, the following SQL, you can never get the result of "type two"
CASE WHEN col_1 IN ( ‘a‘, ‘b‘) THEN ‘第一类‘
WHEN col_1 IN (‘a‘) THEN ‘第二类‘
ELSE‘其他‘ END
Let's take a look at what you can do with the case function.
One, the known data in a different way to group, analysis.
There is the following data: (in order to see more clearly, I did not use the country code, but directly with the country name as primary Key)
Country (country) |
Population (population) |
China |
600 |
United States |
100 |
Canada |
100 |
United Kingdom |
200 |
France |
300 |
Japan |
250 |
Germany |
200 |
Mexico |
50 |
India |
250
|
According to the population data of this country, the population of Asia and North America is counted. The following result should be obtained.
Chau |
Population |
Asia |
1100 |
North america |
250 |
Other |
700
|
What would you do to solve this problem? Creating a view with a continent code is a workaround, but it is difficult to dynamically change the way statistics are used.
If you use the case function, the SQL code is as follows:
SELECT SUM (population),
Case Country
When ' China ' then ' Asia '
When ' India ' Then ' Asia '
When ' Japan ' then ' Asia '
When ' America ' Then ' North America '
When ' Canada ' then ' North America '
When ' Mexico ' then ' North America '
Else ' other ' END
From Table_a
GROUP by Case Country
When ' China ' then ' Asia '
When ' India ' Then ' Asia '
When ' Japan ' then ' Asia '
When ' America ' Then ' North America '
When ' Canada ' then ' North America '
When ' Mexico ' then ' North America '
Else ' other ' END;
Similarly, we can use this method to judge the salary level, and to count the number of each level. The SQL code is as follows:
SELECT
Case when salary <= ' 1 '
When salary > Salary <= 2 '
When salary > Salary <= 3 '
When salary > Salary <= "4"
ELSE NULL END Salary_class,
COUNT (*)
From Table_a
GROUP by
Case when salary <= ' 1 '
When salary > Salary <= 2 '
When salary > Salary <= 3 '
When salary > Salary <= "4"
ELSE NULL END;
Two, a SQL statement to complete the different conditions of the grouping.
Have the following data
Country (country) |
Gender (sex) |
Population (population) |
China |
1 |
340 |
China |
2 |
260 |
US |
1 |
45 |
US |
2 |
55 |
Canada |
1 |
51 |
Canada |
2 |
49 |
UK |
1 |
40 |
UK |
2 |
60 |
Grouped according to country and gender, the results are as follows
Countries |
Man |
Woman |
China |
340 |
260 |
United States |
45 |
55 |
Canada |
51 |
49 |
United Kingdom |
40 |
60
|
In general, a Union can also be used to implement a query with a single statement. But that increases the consumption (two select parts), and the SQL statement is longer.
Here is an example of using the case function to accomplish this function
SELECT country,
SUM( CASE WHEN sex = ‘1‘ THEN
population ELSE 0 END), --男性人口
SUM( CASE WHEN sex = ‘2‘ THEN
population ELSE 0 END) --女性人口
FROM Table_A
GROUP BY country;
Third, use the case function in check.
Using the case function in check is a very good workaround in many cases. There may be a lot of people who don't have check at all, so I suggest you try using check in SQL after reading the following example.
Let's give an example.
Company A, the company has a rule that female employees must pay more than 1000 yuan. If you use check and case to behave as follows
CONSTRAINT check_salary CHECK
( CASE WHEN sex = ‘2‘
THEN CASE WHEN salary > 1000
THEN 1 ELSE 0 END
ELSE 1 END = 1 )
If you simply use check, as shown below
CONSTRAINT check_salary CHECK
( sex = ‘2‘ AND salary > 1000 )
The condition of the female clerk was met, and the male clerk could not enter it.
Four, according to the conditions have selected update.
example, there are the following update conditions
Employees with a salary of more than 5000 are reduced by 10%
Salary increased by 15% for employees between 2000 and 4600
It is easy to consider the option to execute two UPDATE statements as follows
--条件1
UPDATE Personnel
SET salary = salary * 0.9
WHERE salary >= 5000;
--条件2
UPDATE Personnel
SET salary = salary * 1.15
WHERE salary >= 2000 AND salary < 4600;
But it's not as simple as it is supposed to be, assuming a personal salary of 5000 bucks. First of all, according to condition 1, wages are reduced by 10% to 4500 of wages. Next run the second SQL, because this person's salary is 4500 in the range of 2000 to 4600, need to increase 15%, and finally this person's salary result is 5175, not only not reduced, but increased. If the reverse is done, then the wage of 4600 will turn into a wage reduction. No matter how absurd the rules are, if you want an SQL statement to implement this function, we need to use the case function. The code is as follows:
UPDATE Personnel
SET salary = CASE WHEN salary >= 5000
THEN salary * 0.9
WHEN salary >= 2000 AND salary < 4600
THEN salary * 1.15
ELSE salary END;
It is important to note here that the last line of else salary is required, and if there is no such line, the wages of those who do not meet these two conditions will be written as NULL, and that will be a big bad thing. The default value of the else part in the case function is null, which is something to be aware of. This method can also be used in many places, such as changing the primary key dirty.
In general, to the two data primary key,a and B exchange, need to be temporarily stored, copied, read back the data of the three processes, if you use the case function, everything becomes much simpler.
P_key |
Col_1 |
Col_2 |
A |
1 |
Tom |
B |
2 |
John doe |
C |
3 |
Harry
|
Assuming that there is data, you need to exchange the primary key A and B with each other. When implemented with the case function, the code
Under
UPDATE SomeTable
SET p_key = CASE WHEN p_key = ‘a‘
THEN ‘b‘
WHEN p_key = ‘b‘
THEN ‘a‘
ELSE p_key END
WHERE p_key IN (‘a‘, ‘b‘);
The same can be exchanged for two unique keys. It should be noted that if there is a need to exchange the primary key occurs, most of the original design of the table is not in place, it is recommended to check the design of the table is appropriate.
Five, two table data is checked for consistency.
The case function differs from the DECODE function. In the case function, you can use Between,like,is null,in,exists and so on. For example, using in,exists, you can make subqueries to achieve more functionality.
The following example shows that there are two tables, tbl_a,tbl_b, and two tables with KeyCol columns. Now we compare two tables, the data in the KeyCol column in the tbl_a can be found in the data of the KeyCol column in Tbl_b, return the result ' matched ', and if not found, return the result ' unmatched '.
To implement this function, you can use the following two statements
--使用IN的时候
SELECT keyCol,
CASE WHEN keyCol IN ( SELECT keyCol FROM tbl_B )
THEN ‘Matched‘
ELSE ‘Unmatched‘ END Label
FROM tbl_A;
--使用EXISTS的时候
SELECT keyCol,
CASE WHEN EXISTS ( SELECT * FROM tbl_B
WHERE tbl_A.keyCol = tbl_B.keyCol )
THEN ‘Matched‘
ELSE ‘Unmatched‘ END Label
FROM tbl_A;
Six, use the aggregate function in the case function
Suppose you have one of the following tables
School Number (STD_ID) |
Course ID (class_id) |
Course Name (class_name) |
Major in Flag (MAIN_CLASS_FLG) |
100 |
1 |
Economics |
Y |
100 |
2 |
Historical studies |
N |
200 |
2 |
Historical studies |
N |
200 |
3 |
Archaeology |
Y |
200 |
4 |
Computer |
N |
300 |
4 |
Computer |
N |
400 |
5 |
Chemical |
N |
500 |
6 |
Mathematical |
N
|
Some students choose to take several courses at the same time (100,200) Some students choose only one course (300,400,500). Students taking multiple courses are asked to choose a course as their major, with the major flag written in Y. Students who choose only one course, majoring in flag n (in fact, if written in Y, will not have the following trouble, in order to give examples, please include more).
Now we're going to query this table according to the following two conditions
1, the person who only took one course, returned the ID of that course,
2, the person who takes multiple courses, returns the selected master course ID
The simple idea is to execute two different SQL statements to query.
Condition 1: Students with only one course selected
SELECT std_id, MAX(class_id) AS main_class
FROM Studentclass
GROUP BY std_id
HAVING COUNT(*) = 1;
Execution Results 1
STD_ID MAIN_class------ ----------
300 4
400 5
500 6
Condition 2: Students who choose multiple courses
SELECT std_id, class_id AS main_class
FROM Studentclass
WHERE main_class_flg = ‘Y‘ ;
If you use the case function, we can solve the problem with just one SQL statement, as shown below
SELECT std_id,
CASE WHEN COUNT(*) = 1 --只选择一门课程的学生的情况
THEN MAX(class_id)
ELSE MAX(CASE WHEN main_class_flg = ‘Y‘
THEN class_id
ELSE NULL END
)
END AS main_class
FROM Studentclass
GROUP BY std_id;
Run results
STD_ID MAIN_class
------ ----------
100 1
200 3
300 4
400 5
500 6
Identify the QR code in the image and collect the full Python video
In MySQL, case, then else end usage