IOS emoji expression transcoding or judging

If there are comments or information recovery in the project place, often use emoji, sometimes such as the background does not support emoji, will show garbled error, we can turn emoji into Unicode encoding or UTF8 encoding format to the server. Of course, if the background server receives the time can be well judged to identify the best, our side backstage is supported, I only record a method, in case of a rainy day.

First define a Uitextview and set up the proxy

Set a macro definition that is used to determine emoji

#define Mulitthreebyteutf16tounicode (x, Y) (((((((0xD800) << 2) | ((y ^ 0xdc00) >> 8)) << 8) | ((y ^ 0xdc00) & 0xFF)) + 0x10000

What the following write Agent method implements

1-(BOOL) TextView: (Uitextview *) TextView Shouldchangetextinrange: (nsrange) Range Replacementtext: (NSString *) Text2 {3NSString *hexstr =@"";4     5      for(intI=0;i< [Text length];i++)6     {7HEXSTR = [Hexstr Stringbyappendingformat:@"%@", [NSString stringWithFormat:@"0x%1x", [text Characteratindex:i]];8     }9NSLog (@"UTF16 [%@]", hexstr);Ten      OneHexstr =@""; A      -     LongSlen =strlen ([text utf8string]); -      the      for(inti =0; i < Slen; i++) -     { -         //fffffff0 removal of front six F & 0xFF -HEXSTR = [Hexstr Stringbyappendingformat:@"%@", [NSString stringWithFormat:@"0x%X", [Text Utf8string][i] &0xFF ]]; +     } -NSLog (@"UTF8 [%@]", hexstr); +      AHexstr =@""; at      -     if([Text Length] >=2) { -          -          for(inti =0; i < [text length]/2&& ([text length]%2==0) ; i++) -         { -             //three bytes in             if([Text characteratindex:i*2] &0xff00) ==0 ) { -HEXSTR = [Hexstr Stringbyappendingformat:@"ox%1x 0x%1x", [Text characteratindex:i*2],[text characteratindex:i*2+1]]; to             } +             Else -{//Four bytes theHEXSTR = [Hexstr Stringbyappendingformat:@"u+%1x", Mulitthreebyteutf16tounicode ([Text characteratindex:i*2],[text characteratindex:i*2+1])]; *             } $             Panax Notoginseng         } -NSLog (@"(Unicode) [%@]", hexstr); the     } +     Else A     { theNSLog (@"(Unicode) u+%1x", [Text Characteratindex:0]); +     } -      $     returnYES; $}

The input is automatically converted to the appropriate format when it is entered.

If you do not need to enter emoji expression in some places, you can do the relevant restrictions.

What I use here is, if the user input emoji expression, will give a hint

1 //does it contain emoticons ?2-(BOOL) Stringcontainsemoji: (NSString *)string3 {4__block BOOL returnvalue =NO;5     6[stringEnumeratesubstringsinrange:nsmakerange (0, [stringlength])7 options:nsstringenumerationbycomposedcharactersequences8usingblock:^ (NSString *substring, Nsrange substringrange, Nsrange enclosingrange, BOOL *stop) {9                                 ConstUnichar HS = [substring Characteratindex:0];Ten                                 if(0xd800<= HS && HS <=0XDBFF) { One                                     if(Substring.length >1) { A                                         ConstUnichar ls = [substring characteratindex:1]; -                                         Const intUC = (HS-0xd800) *0x400) + (LS-0xdc00) +0x10000; -                                         if(0x1d000<= UC && UC <=0x1f77f) { theReturnValue =YES; -                                         } -                                     } -}Else if(Substring.length >1) { +                                     ConstUnichar ls = [substring characteratindex:1]; -                                     if(ls = =0x20e3) { +ReturnValue =YES; A                                     } at}Else { -                                     if(0x2100<= HS && HS <=0x27ff) { -ReturnValue =YES; -}Else if(0x2b05<= HS && HS <=0x2b07) { -ReturnValue =YES; -}Else if(0x2934<= HS && HS <=0x2935) { inReturnValue =YES; -}Else if(0x3297<= HS && HS <=0x3299) { toReturnValue =YES; +}Else if(HS = =0xa9|| HS = =0xae|| HS = =0x303d|| HS = =0x3030|| HS = =0x2b55|| HS = =0x2b1c|| HS = =0x2b1b|| HS = =0x2b50) { -ReturnValue =YES; the                                     } *                                 } $                             }];Panax Notoginseng      -     returnreturnvalue; the}

By calling this method, if the return is yes then the input contains emoji, and vice versa.

IOS emoji expression transcoding or judging