IplImage and CBitmap Conversion

If you use opencv when writing an mfc program, the conversion between the two is certainly used. I have found a lot on the internet, almost all of which are the same. My situation is a little special, and it is not appropriate to find it for a long time. MD, in one breath, tracked CvvImage: DrawToHDC,

Void IplImage2CBitmap (Iplimage * ipg_src)

{

CBitmap * m_pBitmap = new CBitmap;

If (ipg_src-> depth = IPL_DEPTH_8U)

{

Uchar buffer [sizeof (BITMAPINFOHEADER) + 1024];

BITMAPINFO * bmi = (BITMAPINFO *) buffer;

Int BMP _w = ipg_src-> width, BMP _h = ipg_src-> height;

// FillBitmapInfo (bmi, BMP _w, BMP _h, Bpp (), pImage-> origin );

Int width = BMP _w;

Int height = BMP _h;

Int bpp = ipg_src? (Ipg_src-> depth & 255) * ipg_src-> nChannels: 0;

Int origin = ipg_src-> origin;

HBITMAP hBitmap;

BITMAPINFOHEADER * bmih = & (bmi-> bmiHeader );

Memset (bmih, 0, sizeof (* bmih ));

Bmih-> biSize = sizeof (BITMAPINFOHEADER );

Bmih-> biWidth = width;

Bmih-> biHeight = origin? Abs (height):-abs (height );

Bmih-> biPlanes = 1;

Bmih-> biBitCount = (unsigned short) bpp;

Bmih-> biCompression = BI_RGB;

If (bpp = 8)

{

RGBQUAD * palette = bmi-> bmiColors;

Int I;

For (I = 0; I <256; I ++)

{

Palette [I]. rgbBlue = palette [I]. rgbGreen = palette [I]. rgbRed = (BYTE) I;

Palette [I]. rgbReserved = 0;

}

}

}

The above code is modified from opencv. At this point, you can

HBITMAP hbmp = CreateDIBitmap (pdc-> GetSafeHdc (), bmih, CBM_INIT, ipg_src-> imageData, bmi, DIB_RGB_COLORS );

The first parameter must be the handle of the device to display the image. null indicates memory.

Finally: m_pBitmap-> Attach (hBitmap); if you add

If (m_pBitmap-> m_hObject! = NULL)

{

M_pBitmap-> Detach ();

} Better.

Opencv uses: StretchDIBits (device handle ,......), If you use pdc-> StretchBlt (), it cannot be displayed. Why? Due to limited level!

The Internet is just a reference and you must have your own thoughts. Write some transformations you understand. Although they are also copied, they add their own things.

CBitmap m_bitmap;

HBITMAP h_bmp;

H_bmp = m_bitmap.m_hObject; CBitmap => HBITMAP

M_bitmap = CBitmap: FromHandle (h_bmp); HBITMAP => CBitmap

I tried to convert IplImage directly to CBitmap. This is the code on the Internet, but it was not displayed successfully, and I do not know whether the conversion was successful. Below is the code

IplImage-> CBitmap, Cbitmap-> IplImage

CDC * pdc = this-> GetDC ();

IplImage * img = cvCreateImage (cvSize (100,100), 8, 3 );

CBitmap m_bitmap;

M_bitmap.CreateCompatibleBitmap (pdc, 100,100 );

CDC memdc;

Memdc. CreateCompatibleDC (pdc );

CBitmap * pold = memdc. SelectObject (& m_bitmap );

CvvImage cvimg;

Rect rect (0, 0,100,100 );

Cvimg. CopyOf (img,-1 );

Cvimg. DrawToHDC (memdc. m_hDC, & rect );

ReleaseDC (pdc );

IplImage * tempimg = cvCloneImage (img );

M_bitmap.GetBitmapBits (img-> widthStep * img-> height, img-> imageData );

I tried to display m_bitmap to verify whether the conversion was successful.

Memdc. StretchBlt (0, 0, rect. Width (), rect. Height (), & memdc, 0, 0, w, h, SRCCOPY );

But it didn't work! Not yet clear!