JavaScript (JS) decimal precision lost solution

Reason: JS in accordance with 2 binary to deal with decimal subtraction, on the basis of arg1 arg2 precision extension or inverse extension matching, so the following situation occurs.

JavaScript (JS) decimal point subtraction problem, is a JS bug such as 0.3*1 = 0.2999999999, the following list can be perfect to find the corresponding accuracy of four JS algorithm

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<span style= "font-family:arial, Helvetica, Sans-serif;" >//Division </span>

   function Accdiv (arg1,arg2) {var t1=0,t2=0,r1,r2; Try{t1=arg1.tostring (). Split (".") [1].length}catch (e) {} try{t2=arg2.tostring (). Split (".") [1].length}catch (e) {} with (Math) {R1=number () (Arg1.tostring (). Replace (".", "")) R2=number (Arg2.tostring (). Replace ("."   , "")) return Accmul ((R1/R2), pow (10,T2-T1));    }}//Multiplication function Accmul (arg1,arg2) {var m=0,s1=arg1.tostring (), s2=arg2.tostring (); Try{m+=s1.split (".") [1].length}catch (e) {} try{m+=s2.split (".") [1].length}catch (e) {} return Number (S1.replace (".", "")) *number (S2.replace (".", ""))/math.pow (10,M)}//addition function  Accadd (arg1,arg2) {var r1,r2,m; Try{r1=arg1.tostring (). Split (".") [1].length}catch (e) {r1=0} try{r2=arg2.tostring (). Split (".")     [1].length}catch (e) {r2=0} m=math.pow (10,math.max (R1,R2)) return (arg1*m+arg2*m)/m}//Subtraction function subtr (ARG1,ARG2) {     var r1,r2,m,n; Try{r1=arg1.tostring (). Split (".") [1].length}catch (e) {r1=0} try{r2=arg2.tostring (). Split (".") [1].length}catch (e) {r2=0} m=Math.pow (10,math.max (R1,R2));     N= (R1>=R2) r1:r2; Return ((arg1*m-arg2*m)/m). ToFixed (n); }

JavaScript (JS) decimal precision lost solution