JavaScript regular judgment Password type (pure alphanumeric start + any character)

Let's take a look at the regular rules.

Text

/^ (\d+) $/corresponds to "pure digits"
/^ ([a-za-z]+) $/corresponds to "pure letter"
/^ ([a-za-z].+) $/corresponds to "beginning of letter + any character"
/^ ([0-9a-za-z]+) $/corresponds to "number + letter any combination"
/^ ([\s\s]+) $/corresponding "not categorized"

Example

The code is as follows	Copy Code
function Test (str, RE, msg) { var ret = Str.match (Re | |/^ (\d+) $|^ ([a-za-z]+) $|^ ([a-za-z].+) $|^ ([0-9a-za-z]+) $|^ ([\s\s]+) $/); var msg = MSG | | ["", "pure digit", "pure Letter", "beginning of letter + any character", "number + letter any combination", "not classified"]; var i = 0; while (ret[++i] = = undefined); return msg[i]; }

Test

The code is as follows	Copy Code
Console.log (Test ("123")); Console.log (Test ("SSS")); Console.log (Test ("123xx")); Console.log (Test ("a123xx")); Console.log (Test ("%$#@"));

You can see that using a regular and an array completes the effectiveness.
In fact, the idea is very simple, using the regular capture group to correspond to the characters in the array.

code is as follows	copy code
/^ (\d+) $|^ ( [a-za-z]+) $|^ ([a-za-z].+) $|^ ([0-9a-za-z]+) $|^ ([\s\s]+) $/