Js get time difference remove implementation code on Saturday and Sunday

Copy codeThe Code is as follows:
Function GetDayNum (no, type ){
If (type = "35 "){
Var num7 = document. getElementById ("6"). value;
Var value = document. getElementById ("7"). value;
Var valueR = num7;
If (no = "7") {valueR = value;} // identifies the time value
If (num7! = "" & Value! = "") {// The BUG1 can be integrated in two time periods
Var numValue = 0;
Var numValue = 0;
Var day = 24*60*60*1000;
Var dateArr = value. split ("-");
Var checkDate = new Date ();
CheckDate. setFullYear (dateArr [0], dateArr [1]-1, dateArr [2]);
Var checkTime = checkDate. getTime ();
Var dateArr2 = num7.split ("-");
Var checkDate2 = new Date ();
CheckDate2.setFullYear (dateArr2 [0], dateArr2 [1]-1, dateArr2 [2]);
Var checkTime2 = checkDate2.getTime ();
Var numValue = (checkTime-checkTime2)/day; // The total number of days of the difference

Var totleWeek = numValue/7; // how many weeks are different?
Var yuDay = numValue % 7; // except for the day of the week
Var lastDay = 0;
Var startWeek = num7.replace (/-/g, "/"); // change "-" to "/", where "-" is not accurate. I tested it.
// Var date = new Date (parseInt (startWeek [0]), parseInt (startWeek [1]), parseInt (startWeek [2]);
Var date = Date. parse (startWeek );
Var dateNew = new Date (date );
Var weekDay = dateNew. getDay (); // day of the week
Var endWeekDay = 0; // the remaining days are Saturday or Sunday.
If (weekDay = 6 & yuDay> = 2) | (weekDay = 7 & yuDay> = 1) | (weekDay = 5 & yuDay> = 3) | (weekDay = 4 & yuDay> = 4) | (weekDay = 3 & yuDay> = 5) | (weekDay = 2 & yuDay> = 6) | (weekDay = 1 & yuDay> = 7 )){
EndWeekDay = 2; www.jb51.net
}
If (weekDay = 6 & yuDay <1) | (weekDay = 7 & yuDay <5) | (weekDay = 5 & yuDay <2) | (weekDay = 4 & yuDay <3) | (weekDay = 3 & yuDay <4) | (weekDay = 2 & yuDay <5) | (weekDay = 1 & yuDay <6 )){
EndWeekDay = 1;
}
// If (numValue = 0) {numValue = 1 ;}
NumValue = numValue-(totleWeek * 2)-endWeekDay; // the final time.

}
}
}