Json.NET Simple to use

Json. NET (http://json.codeplex.com/) is used to set the. NET objects into JSON strings (serialized?). ), or convert the JSON string to an object of an existing type in. NET (deserialization?). ）

First, for example, define a type casually:

public class product{Public    string Name {get; set;}    Public DateTime expiry {get; set;}    Public decimal price {get; set;}    Public string[] Sizes {get; set;}    public override string ToString ()    {        return string. Format ("name:{0},expiry:{1},price:{2},sizescount:{3}"            , Name, expiry, price, sizes.length);    }

Initialize the object:

public static void Main (string[] passwordargs) {    Product product = new Product ()    {        Name = "Android",        Expiry = DateTime.Now, Price        = $,        Sizes = new string[] {"1.5", "2.2", "4.1"}    };}

To convert to JSON:

Console.WriteLine (Jsonconvert.serializeobject (product));

Output Result:

{"Name": "Android", "expiry": "2013-08-30t09:50:11.5147845+08:00", "Price": 2000.0, "Sizes": ["1.5", "2.2", "4.1"]}

Everything else looks normal except for this date a little strange

Formatted Date:

Format date time, same as ToString format for datatime type Isodatetimeconverter ISO = new isodatetimeconverter (); ISO. DateTimeFormat = "Yyyy-mm-dd HH:mm:ss"; Console.WriteLine (Jsonconvert.serializeobject (product, ISO));

Output Result:

{"Name": "Android", "expiry": "2013-08-30 09:53:58", "Price": 2000.0, "Sizes": ["1.5", "2.2", "4.1"]}

Conversion from JSON to object:

String str = "{\" name\ ": \" android\ ", \" expiry\ ": \" 2013-08-30 09:53:58\ ", \" price\ ": 2000.0,\" sizes\ ": [\" 1.5\ ", \" 2.2\ " , \ "4.1\"]} "; Product P = (product) jsonconvert.deserializeobject (str, typeof (product)); Console.WriteLine (P.tostring ());

Output Result:

Name:android,expiry:2013/8/30 9:53:58,price:2000.0,sizescount:3

Conversion from JSON to key-value pairs:

String Strjson = @ "{" "Name1" ":" "Xiao Ming" "," "Name2" ":" "Floret" "," "Name3" ":" "Little Red" "}";D ictionary<string, String> _ Dictionary = jsonconvert.deserializeobject<dictionary<string, string>> (Strjson); foreach (KeyValuePair <string, string> KP in _dictionary) {    Console.WriteLine (KP. Key + ":" + KP. Value);}

Output Result:

Name1: Xiao Ming
Name2: Xiao Hua
Name3: Xiao Hong

Converting from a string to a JSON object, as well as a simple use of a JSON object:

String strJson2 = @ "{" "Student" ": {" "Name1" ":" "Xiao Ming" "," "Name2" ":" "Floret" "," "Name3" ":" "Little Red" "}}"; Jobject jsonobj = Jobject.parse (StrJson2); Console.WriteLine (jsonobj["Student" ["Name1"]. ToString ()); Console.WriteLine (jsonobj["Student" ["Name2"]. ToString ()); Console.WriteLine (jsonobj["Student" ["Name3"]. ToString ());

Output Result:

Xiao ming
Small flower
Little Red

To generate a JSON object directly:

Jobject json =    new Jobject (New    jproperty ("Channel",        new Jobject (New        jproperty ("title", "JSON"), New        Jproperty ("link", "json.net"),        new Jproperty ("description", "Json.NET description"),        new Jproperty ( "Items", New            Jarray (new            jobject ("Haha1", "123"),            new Jobject ("Jproperty", "456" )),            new Jobject (New Jproperty ("Haha3", "789")))))                ; Console.WriteLine (JSON. ToString ());

Output Result:

{
"Channel": {
"title": "JSON",
"Link": "Json.NET",
"description": "Json.NET description",
"Items": [
{
"HAHA1": "123"
},
{
"HAHA2": "456"
},
{
"HAHA3": "789"
}
]
}
}

So much for the time being, and then we'll keep adding.