Known n number of the and is 32898, for each addend, for the perfect version

Source: Internet
Author: User
The original posts have been affixed to the knot. Just get the result is not perfect, always the maximum number 999 repeats too much, seems not enough random, a little fake.
http://bbs.csdn.net/topics/391814341

$r = foo (32898), Echo array_sum ($r), Php_eol; Verify the Sum Print_r (array_count_values ($r)); View distribution function foo ($num, $k, $min =1, $max =999) {  $res = Array_fill (0, $k, 1);  Do {for    ($i =0; $i < $k; $i + +) {      $sum = array_sum ($res);      $t = rand (0, $max-$min);      if ($res [$i] + $t > $max) $t = $max-$res [$i];      if ($sum + $t > $num) $t = $num-$sum;      $res [$i] + = $t;    }  } while ($num > $sum);  return $res;}


Please fix this problem, thank you.


Reply to discussion (solution)

$t = rand (0, $max-$min);
Switch
$t = rand (0, $max-$res [$i]);

It's supposed to be a good distribution.

Array (    [886] = 1    [760] = 1    [470] = 1    [875] = 1    [591] = 1    [499] = 1    [25 7] = 1    [954] = 1    [~] + 1    [615] = 1    [770] = 1    [644] = 1    [971] = 1< C13/>[979] + 1    [259] = 1    [906] = 1    [830] = 1    [537] = 1    [595] = 1    [53  1] = 1    [588] = 1    [748] = 1    [767] = 1    [844] = 1    [931] = 1    [835] = 1    [986] + 1    [976] = 1    [[] + 1    [157] + 1    [408] = 1    [582] + 1    [ 593] + 1    [876] = 1    [710] = 1    [[] = 1    [554] = 1    [774] = 1    [386] =&G T 1    [339] = 1    [686] = 1    [194] = 1    [903] = 1    [304] = 1    [207] + 1    [ 978] + 1    [232] = 1    [618] = 1    [834] = 1    [472] = 1    [839] = 1    [377] =&G T 1    [788] = 1)
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