Leecode aoti, leecodeaoti

Leecode aoti, leecodeaoti

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Recently, I found that my ability to write code is greatly reduced. So, I checked online to see if there are any projects that can be improved. It is particularly interesting to see other people brush questions on leetcode. Because each question on leetcode has many test cases, all the code you upload must pass these test cases.

Not to mention, to avoid shame. Start with an easy question. Atoi is actually the code for converting a string into an integer. It is easy to look at, but it is not easy, because you need to consider various situations, in fact, this is very helpful for us to improve the quality of code. You can write the code in cpp, java, or python format as needed.

Because the vc compiler is not installed on my machine, I can only adjust it based on the feedback from the website. It took nearly one and a half hours to read the logs. I have been working for so many years, this score is still very shameful. You can try the leetcode according to your own needs. If you see this blog, it is best not to read the code first. You can try it yourself to see if you can maximize the performance while ensuring the correctness.

In order not to infringe on the copyright of the original author, I am only here to give my personal understanding and answers to the question. Of course, it is just a reference.

#inlude <iostream>using namespace std;class Solution {public:static int atoi(const char* str) {int index = 0;int neg = 0;int total = 0;int len = strlen(str);char val  = 0;int count = 0;if(!len) return total;while(str[index] == ' ')index ++;if(str[index] == '+') index ++;else if(str[index] == '-') {neg = 1;index++;}for(; index < len; index ++) {val = str[index] - '0';count ++;if(val < 0 || val > 9)break;if(count > 10) {if(neg) total = 0x80000000;else total = 0x7fffffff;goto end;}if(!neg && count == 10) {if(val > (0x7fffffff - total * 10)) {total = 0x7fffffff;goto end;}}else if(neg && count == 10){if((unsigned int)val > (unsigned int)((-total * 10) - (int)(0x80000000))) {total = 0x80000000;goto end;}}total = total * 10 + val;}if (neg) total = -total;end:return total;}};