[LeetCode-interview algorithm classic-Java implementation] [013-Roman to Integer (Roman to Integer)], leetcode -- java

[LeetCode-interview algorithm classic-Java implementation] [013-Roman to Integer (Roman to Integer)], leetcode -- java
[013-Roman to Integer (Roman to Integer )][LeetCode-interview algorithm classic-Java implementation] [directory indexes for all questions]Original question

Given a roman numeral, convert it to an integer.
Input is guaranteed to be within the range from 1 to 3999.

Theme

Given a roman number, convert it to the corresponding integer.
The entered number is between 1 and.

Solutions

The addition operation is performed based on the ing relationship between the number of Rome and the number of integers. If the first number is greater than the last one, the addition operation is performed.

Code Implementation

Public class Solution {public int romanToInt (String s) {int result = 0; int prev = 0; // record the value of the previous number for (int I = s. length ()-1; I>-1; I --) {switch (s. charAt (I) {case 'I': // 1 if (1 <prev) {result-= 1;} else {result + = 1;} prev = 1; break; case 'V': // 5 if (5 <prev) {result-= 5;} else {result + = 5;} prev = 5; break; case 'X': // 10 if (10 <prev) {result-= 10;} else {result + = 10;} prev = 10; break; case 'l ': // 50 if (50 <prev) {result-= 50;} else {result + = 50;} prev = 50; break; case 'C ': // 100 if (100 <prev) {result-= 100;} else {result + = 100;} prev = 100; break; case 'D ': // 500 if (500 <prev) {result-= 500;} else {result + = 500;} prev = 500; break; case 'M ': // 1000 result + = 1000; prev = 1000; break;} return result ;}

Evaluation Result

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Note Please refer to the following link for more information: http://blog.csdn.net/derrantcm/article/details/46963377]

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