# [LeetCode-interview algorithm classic-Java implementation] [075-Sort Colors (Color Sorting)], leetcode -- java

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[LeetCode-interview algorithm classic-Java implementation] [075-Sort Colors (Color Sorting)], leetcode -- java
[075-Sort Colors (Color Sorting )][LeetCode-interview algorithm classic-Java implementation] [directory indexes for all questions]Original question

Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note:
You are not suppose to use the library's sort function for this problem.

Theme

Given an array of objects, the objects are red, white, and blue. Sort the colors, red, white, and blue.
Use 0, 1, and 2 to represent red, white, and blue respectively.
Note:The database function cannot be used for sorting.

Solutions

Scan the array and count the number of records 1 and the sum of the entire array. After scanning, we can get the number t of 1, the number of 2 (sum-t)/2, and the number of 0, 2 and then set the value of the array.

Code Implementation

Algorithm Implementation class

``Public class Solution {public void sortColors (int [] A) {if (A = null) {return;} int count = 0; // count the number of 1 int sum = 0; // count the sum of the array and for (int I: A) {if (I = 1) {count ++ ;} sum + = I;} sum = (sum-count)/2; // calculate the number of 2 count =. length-count-sum; // the position where 1 begins to appear. sum =. length-sum; // the position where 2 starts to appear for (int I = 0; I <count; I ++) {A [I] = 0 ;} for (int I = count; I <sum; I ++) {A [I] = 1 ;}for (int I = sum; I <. length; I ++) {A [I] = 2 ;}}}``
Evaluation Result

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