$line [1] = Intval ($line [1]); What does this mean by writing this?

   <title>Bob ' s Auto parts-customer Orders</title>
Bob ' s Auto Parts
Customer Orders

 No orders pending. Please try again later.
"; } echo "
 
 
  
  \ n "; echo "
  
   Oil 
     Total 
    
     "; for ($i =0; $i < $number _of_orders; $i + +) {//split up all line $line = explode ("\ t", $orders [$i]); Keep only the number of items ordered $line [1] = Intval ($line [1]); $line [2] = Intval ($line [2]); $line [3] = Intval ($line [3]); Output each order echo " 
   "; } echo " 
  
 
   
 
    
Order Date
 
    
Tires
 
    
Spark Plugs
 
    
Address
 
   
 
   
 
   
 
    
". $line [0]."
 
    
". $line [1]."
 
    
". $line [2]."
 
    
". $line [3]."
 
    
". $line [4]."
 
    
". $line [5]."
 
   
 
 
";? >

$line [1] = Intval ($line [1]); What does this mean by writing this? The Intval manual is the integer value that describes intval returns the variable var by using a specific binary conversion (by default, decimal). But what is the effect of assigning this integer value to $line[1]?

Reply to discussion (solution)

The intval () variable turns into an integer type $line[1] = Intval ($line [1]); $line [2] = Intval ($line [2]), $line [3] = Intval ($line [3]), and a variable that converts to an integer type to regroup an array $line you can also reassign the variable $line_a = intval ($line [1] ); $line _b = Intval ($line [2]), $line _c = Intval ($line [3]); Then your template shows that the corresponding needs change.

$line [1] = Intval ($line [1]);
Ensures that the value of the final $line [1] is an integer

Besides, the original author has already made a statement
38 lines have keep only the number of items ordered

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