Methods for obtaining the current directory in the JSP

This article describes the JSP to obtain the current directory implementation methods, share for everyone to reference. The implementation methods are as follows:

1, using the System.getproperty () function to get the current path:

The code is as follows:

System.out.println (System.getproperty ("User.dir"));//user.dir specified the current path

2, use the function provided by the file to get the current path:

The code is as follows:

File directory = new file ("");//Set as current folder

try{

System.out.println (Directory.getcanonicalpath ());//Get the standard path

System.out.println (Directory.getabsolutepath ());//Get absolute path

}catch (Exceptin e) {}

File.getcanonicalpath () and File.getabsolutepath () are about just the new File (".") and new File ("..") There is a difference between these two paths.

# for the Getcanonicalpath () function, "." Represents the current folder, and the "..." Represents the folder up to the current folder

# for the GetAbsolutePath () function, regardless of ".", "...", return the current path plus the path you set at New File ()

# As for the GetPath () function, you get only the path you set at New File ()

For example, the current path is c:test:

The code is as follows:

File directory = new file ("abc");

Directory.getcanonicalpath (); Got a c:testabc.

Directory.getabsolutepath (); Got a c:testabc.

Direcotry.getpath (); I got ABC.

File directory = new file (".");

Directory.getcanonicalpath (); Got a c:test.

Directory.getabsolutepath (); Get the c:test.

Direcotry.getpath (); Get is.

File directory = new file ("..");

Directory.getcanonicalpath (); Get the C:

Directory.getabsolutepath (); Get the c:test.

Direcotry.getpath (); Get a..

Get the current working directory for JAVA Programs

The code is as follows:

File File = new file ("T.tmp");

String FullPath = File.getabsolutepath ();

①request.getrealpath:

Method: Request.getrealpath ("/")

The resulting path: C:Program filesapache Software foundationtomcat 5.5webappsstrutsTest

Method: Request.getrealpath (".")

The resulting path: C:Program filesapache Software foundationtomcat 5.5webappsstrutsTest.

Method: Request.getrealpath ("")

The resulting path: C:Program filesapache Software foundationtomcat 5.5webappsstrutsTest

Method: Request.getrealpath ("Web.xml")

The resulting path: C:Program filesapache Software foundationtomcat 5.5webappsstrutstestweb.xml

②request.getparameter ("");

Actionform.getmyfile ();

Method: String filepath = request.getparameter ("MyFile");

The resulting path: D:vss installation directory Users.txt

Method: String filepath = Actionform.getmyfile ();

The resulting path: D:vss installation directory Users.txt

I hope this article will help you with the JSP program design.