MySQL by year, Quarter, month, week, day SQL statistics query

Description

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select year ( ' 2014-10-29 ' //2014 select month ( ' 2014-10-29 ' //10 Select day ( ' 2014-10-29 ' //29 select quarter ( ' 2014-10-29 ' //4    quarter select dayofweek ( ' 2014-10-29 '   //4    week

I. Annual ENQUIRY
Querying data for the year

123	SELECT *FROM blog_articleWHERE year( FROM_UNIXTIME( BlogCreateTime ) ) = year( curdate( ))

Second, query quarterly data
Number of quarters with query data included

12	SELECT ArticleId, quarter( FROM_UNIXTIME( `BlogCreateTime` ) )FROM `blog_article`

Other previous sections: Querying data for the quarter

123	SELECT *FROM blog_articleWHERE quarter( FROM_UNIXTIME( BlogCreateTime ) ) = quarter( curdate( ))

Third, query monthly data
Monthly Statistics (MySQL)

12	select* from booking where month(booking_time) =month(curdate()) and year(booking_time) = year(curdate())

Weekly Stats (MySQL)

12	select* from spf_booking where month(booking_time) =month(curdate()) and week(booking_time) = week(curdate())

Iv. time period
N Days of recording

1	WHERE TO_DAYS(NOW()) - TO_DAYS(时间字段) <= N

Record of the day

1	where date(时间字段)=date(now())

Or

1	where to_days(时间字段) = to_days(now());

Query one week

1	select* from table   where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(column_time);

Query one months

1	select* from table where DATE_SUB(CURDATE(), INTERVAL INTERVAL 1 MONTH) <= date(column_time);

Query ' 06-03 ' to ' 07-08 ' for all birthdays during this time period:

12	Select * From user WhereDATE_FORMAT(birthday,‘%m-%d‘) >= ‘06-03‘and DATE_FORMAT(birthday,‘%m-%d‘)<= ‘07-08‘;

Statistics quarterly data, table Time field: Savetime

1	group by concat(date_format(savetime, ‘%Y ‘),FLOOR((date_format(savetime, ‘%m ‘)+2)/3))

Or

123	selectYEAR(savetime)*10+((MONTH(savetime)-1) DIV 3) +1,count(*)from yourTablegroup by YEAR(savetime)*10+((MONTH(savetime)-1) DIV 3) +1;

Five, group query
1. Group of the Year
2. Monthly Group
3, first group by year, and then by the monthly group
4. GROUP BY month

1	SELECT count(ArticleId), date_format(FROM_UNIXTIME( `BlogCreateTime`),‘%y%m‘) sdate  FROM `blog_article` group by sdate

Results:

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Count ( ArticleId )      sdate  17      0901  11     0902  5     0903  6      0904  2     0905  1     0907   12     0908  6      0909  11     0910  3     0911

Other method references:
I want to do a statistic, the database is MySQL, the daily, weekly, monthly number of records
when the table is created by adding a field to indicate the date, and then check the SQL manual ...

123	select  count (*)  from  ' table '  where  ' date ' = ' {One day} ' Select  count (*)  from  ' table '  where date_format (' date %V ' ) = ' {a week} ' Select  count (*)  from  ' table '  where date_format (' date ) = ' {a month} '

Another way:

12	selectcount( * ) from projects where editdate >= ‘2007-11-9 00:00:00‘and editdate <=‘2007-11-9 24:00:00‘;

The third method:
of the Week

12	SQL codeselect count(*) as cnt,week(editdate) as weekflg from projects where year(editdate)=2007 group by weekflg

Monthly

12	SQL codeselect count(*) as cnt,month(editdate) as monthflg from projects where year(editdate)=2007 group by monthflg

Every day

1	SQL codeselect count(*) as cnt from projects group by date(editdate)

MySQL date_format (date, format) functions can format date or date and time values according to the format string and return the result
String.
You can also use Date_format () to format a date or datetime value to get the format you want. Format according to format string
Date value:
Here is the parameter description for the function:

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%S, %s 两位数字形式的秒（ 00,01, . . ., 59）%i 两位数字形式的分（ 00,01, . . ., 59）%H 两位数字形式的小时，24 小时（00,01, . . ., 23）%h, %I 两位数字形式的小时，12 小时（01,02, . . ., 12）%k 数字形式的小时，24 小时（0,1, . . ., 23）%l 数字形式的小时，12 小时（1, 2, . . ., 12）%T 24 小时的时间形式（hh : mm : s s）%r 12 小时的时间形式（hh:mm:ss AM 或hh:mm:ss PM）%p AM 或P M%W 一周中每一天的名称（ Sunday, Monday, . . ., Saturday）%a 一周中每一天名称的缩写（ Sun, Mon, . . ., Sat）%d 两位数字表示月中的天数（ 00, 01, . . ., 31）%e 数字形式表示月中的天数（ 1, 2， . . ., 31）%D 英文后缀表示月中的天数（ 1st, 2nd, 3rd, . . .）%w 以数字形式表示周中的天数（ 0 = Sunday, 1=Monday, . . ., 6=Saturday）%j 以三位数字表示年中的天数（ 001, 002, . . ., 366）% U 周（0, 1, 52），其中Sunday 为周中的第一天%u 周（0, 1, 52），其中Monday 为周中的第一天%M 月名（January, February, . . ., December）%b 缩写的月名（ January, February, . . ., December）%m 两位数字表示的月份（ 01, 02, . . ., 12）%c 数字表示的月份（ 1, 2, . . ., 12）%Y 四位数字表示的年份%y 两位数字表示的年份%% 直接值“%”

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from:http://hfreeze.blog.51cto.com/1639680/1569278

MySQL by year, Quarter, month, week, day SQL statistics query