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There are many ways to assemble strings in the go language, so the question is, which is the best performance?
The following code, respectively, compares the FMT. Sprintf,string +,strings. Join,bytes. Buffer, the method is to loop several times the total time of comparison.
The results of the operation under the Ubuntu 14.04 under VMware Show:
- Fmt. Sprintf and strings. Join speed is quite
- String + one times faster than the above
- bytes. And the buffer is about 400-500 times faster than the last person.
- If a bytes is temporarily declared within a loop. Buffer to use, will be 50% slower than persistent, but still very fast
The test code is as follows:
Package Mainimport ("bytes" "FMT" "Strings" " Time") func benchmarkstringfunction (nint, indexint) (d time. Duration) {V:="ni shuo wo shi bu shi tai wu liao le a?" varSstring varbuf bytes. Buffer T0:=Time . Now () forI: =0; I < n; i++ { SwitchIndex { Case 0://FMT. Sprintfs = fmt. Sprintf ("%s[%s]", S, v) Case 1://string +s = s +"["+ V +"]" Case 2://strings. Joins = strings. Join ([]string{s,"["V"]"},"") Case 3://Temporary bytes. BufferB: =bytes. buffer{} b.writestring ("[") b.writestring (v) b.writestring ("]") s=b.string () Case 4://Stable bytes. BufferBuf. WriteString ("[") buf. WriteString (v) buf. WriteString ("]") } ifi = = N1 { ifindex = =4{//For stable bytes. Buffers =buf. String ()} FMT. Println (Len (s))//consume s to avoid compiler optimization}} T1:=Time . Now () d=t1. Sub (t0) fmt. Printf ("Time of the (%d) =%v\n", index, D)returnD}func Main () {k:=5D:= [5]time. duration{} forI: =0; I < K; i++{D[i]= Benchmarkstringfunction (10000, I)} forI: =0; I < K1; i++{fmt. Printf ("The on-the-%6.1f times of the- %d\n", I, float32 (D[i])/float32 (d[k-1]), K-1) }}
One of the results was as follows:
etworker@ubuntu:~/work/go/test$ Go run testbenchmark.go410000Time of the -0)=1. 199641573s410000Time of the -1)=568. 716669ms410000Time of the -2)=1. 197077483s ATime of the -3)=2. 277063ms410000Time of the -4)=1. 398864msway0 is 857.6Times of the4 the1 is 406.6Times of the4 the2 is 855.7Times of the4 the3 is 1.6Times of the4