Title Description
Some schools connect to a computer network. The schools have agreed that each school will distribute software (known as "school acceptance") to some other schools. Note Even if B is in the distribution list of school A, a is not necessarily in the list of B schools.
You have to write a program calculation, according to the Protocol, in order to allow all schools in the network to use the new software, you must accept the minimum number of new software copies of the school (subtask A). Further, we want to make sure that by sending new software to any school, the software is distributed to all schools on the network. In order to complete this task, we may have to expand the receiving school list to join the new members. The calculation requires a minimum of several extensions, so that no matter which school we send new software to, it will reach all the rest of the school (subtask B). An extension is the introduction of a new member in a school's receiving school list.
Input/output format
Input format:
The first line of the input file includes an integer n: the number of schools in the network (2 <= N <= 100). The school is identified with the first N positive integers.
Each row in the next N row represents a Receive school list (distribution list). Line i+1 includes an identifier for school I's receiving school. Each list ends with 0. An empty list is represented by only one 0.
Output format:
Your program should output two lines in the output file.
The first line should include a positive integer: The solution of subtask A.
The second line should include the solution of sub-task B.
Input and Output Sample input example # #:
52 4 3 04 5 0001 0
Sample # # of output:
12
Description
The title translation comes from Nocow.
Usaco Training Section 5.3
#include <cstdio>#include<stack>#include<algorithm>#include<vector>#defineMAXN 10001using namespacestd;intN,M,LOW[MAXN],DFN[MAXN],SCCNO[MAXN],DEP,SCC,inch[MAXN], out[Maxn],inc,outc;stack<int> s;//stack can effectively prevent the original image from being destroyedvector<int>G[MAXN];voidTintu) {dfn[u]=low[u]=++dep;//-- S.push (U);//u queue for(intI=0; I<g[u].size (); + +i) { intv=G[u][i]; if(!dfn[v]) T (v), Low[u]=min (Low[u],low[v]);//v Targan and update if not accessed v Low[u] Else if(!sccno[v]) low[u]=min (Low[u],dfn[v]);//Otherwise, if V is not strongly connected, update}if(low[u]==Dfn[u]) { ++SCC;//SCC is a strong connected number recorder while(1){intX=s.top (); S.pop (); SCCNO[X]=SCC;//mark the strong connected serial number that belongs to and out of the team (erase) if(X==u) Break;/*out of the squad .*/}}}intMain () {inti,j; scanf ("%d",&N); for(i=1; i<=n;++i) for(SCANF ("%d", &j); J;SCANF ("%d", &j)) G[i].push_back (j);//Magic Input Method for(i=1; i<=n;++i)if(!Dfn[i]) t (i); for(i=1; i<=n;++i) for(j=0; J<g[i].size (); + +j) { intv=G[i][j]; if(Sccno[i]!=sccno[v]) + +inch[sccno[v]],++ out[Sccno[i]];//Strong connected graph after the connection is indented, update in degree, out degree } for(i=1; i<=scc;++i) inc+=inch[i]==0?1:0, outc+= out[i]==0?1:0;//If the entry is 0, add Inc, if the degree is 0, add OUTC if(scc==1) puts ("1\n0");//in special cases, there is only one strong connected graph, which is itself a strong connected graph. Elseprintf"%d\n%d\n", Inc,max (INC,OUTC));return 0;//Otherwise, the normal output}
Program was just above,the program was the best language
P2746 [USACO5.3] Campus Network of schools