Title Description
In a 4*4 box placed a number of the same toys, someone want to rearrange these toys into his ideal state, the movement can only move the toys up and down in four directions, and move the position can not have toys, please use the minimum number of moves to move the initial toy state to the target state of someone's heart.
input/output format
Input Format:
The first 4 lines indicate the initial state of the toy, 4 digits per line 1 or 0, 1 means the toy is placed in the square, and 0 means no toys are placed. Then there is a blank line. The next 4 lines indicate the target state of the toy, 4 digits 1 or 0 per line, with the same meaning.
output Format:
An integer that requires a minimum number of moves.
input/Output sample
Input Sample # #:
1111000011100010 1010010110100101
Sample # # of output:
4
Solution:
The subject compares the water , but I adjust quickly the mentality burst. (Because of the variable name of the problem, the wrong number of variables, make it always thought that the hand of the queue is wrong, alas ~ too dish ~!) )
From a certain state to another State, and given the transfer method, it is not difficult to think, general direct wide search on the $ok$.
The key is how to weigh and record the state, at this time because each state is a $16$ bit $0/1$ string, it is natural to think of state compression: with $1$ to $2^{16}=65536$ to record each state, burst search $ac$. As for how to transfer the direct simulation well! (I am more stupid, the method is more cumbersome, say the hand pushed a wave of transfer process, ~ funny ~)
Code:
1#include <bits/stdc++.h>2 #definefor (I,A,B) for (int (i) = (a);(i) <= (b);(i) + +)3 using namespacestd;4 Const intn=65560;5 intst,ed,op[ -],opt,mp[n],ans;6 intdx[ -][4]={7 0,0,0,0, 8 1,4,0,0, 9-1,1,4,0, Ten-1,1,4,0, One-1,4,0,0, A-4,4,1,0, --1,1,4,-4, --1,1,4,-4, the-4,4,-1,0, --4,4,1,0, --1,1,4,-4, --1,1,4,-4, +-4,4,-1,0, --4,1,0,0, +-4,-1,1,0, A-4,-1,1,0, at-4,-1,0,0 - }; -queue<int>Q; - Chars; - BOOLVis[n]; - intMain () { inIos::sync_with_stdio (0); -for (I,1, -) cin>>s,st= (st<<1) +s-'0'; tofor (I,1, -) cin>>s,ed= (ed<<1) +s-'0'; +Q.push (ST); vis[st]=1; - while(!Q.empty ()) { the intU=q.front (); Q.pop ();intp=u; * if(u==ed) Break; $for (I,1, -) {op[ --i]=p%2, p>>=1;}Panax Notoginsengfor (I,1, -) for (J,0,3) - if(dx[i][j]!=0){ the if(op[i+dx[i][j]]!=Op[i]) { +Swap (op[i+dx[i][j]],op[i]); Aopt=0; theFor (K,1, -) opt= (opt<<1)+Op[k]; + if(!vis[opt]) { -vis[opt]=1, Q.push (opt), mp[opt]=mp[u]+1; $ } $Swap (op[i+dx[i][j]],op[i]); - } - } the } -cout<<mp[ed];Wuyi return 0; the}
P4289 [HAOI2008] Mobile Toys