Pat B 1018. Hammer and scissors cloth (20)

1018. Hammer and Scissors cloth (20) time limit MS Memory limit 65536 KB code length limit 8000 B procedure StandardAuthor Chen, Yue

Everyone should play "Hammer and Scissors Cloth" game: two people at the same time give gestures, the rule of victory:

Now give a record of the confrontation between two people, please count the wins, flat, negative number of both sides, and give the two sides what gesture of the greatest odds.

Input format:

Enter line 1th to give the positive integer n (<=105), that is, the number of times the two sides clash. Then n lines, each row gives the information of a confrontation, that is, a, b both sides of the gesture given at the same time. C for "Hammer", J for "Scissors", B for "cloth", 1th letter for party A, 2nd for party B, 1 spaces in the middle.

Output format:

Output 1th, 2 respectively give a, B wins, flat, negative times, the number between 1 spaces separated. The 3rd line gives two letters, representing the most winning gestures of A and b, with 1 spaces in the middle. If the solution is not unique, the solution with the smallest alphabetic order is output.

Input Sample:

10C JJ BC bb bb cc cc BJ BB CJ J

Sample output:

5 3 3 5B B

1#include"stdio.h"2#include"string.h"3#include <stdlib.h>4 intMain ()5 {6     inti,b,ap=0, awin_c=0, awin_b=0, awin_j=0, alose_b=0, alose_c=0, alose_j=0;7     Charstr0,str2;8scanf"%d",&b);9      for(i=0; i<b;i++){TenGetChar ();//Enter Onescanf"%c%c",&str0,&str2); A         if(str0=='C') -         { -             if(str2=='C') theap++;//Draw -             if(str2=='J') -awin_c++;//a C win -             if(str2=='B') +alose_b++;//B wins -         } +         if(str0=='B') A         { at             if(str2=='B') -ap++; -             if(str2=='C') -awin_b++; -             if(str2=='J') -alose_j++; in         } -         if(str0=='J') to         { +             if(str2=='J') -ap++; the             if(str2=='B') *awin_j++; $             if(str2=='C')Panax NotoginsengAlose_c++; -         } the  +     } A  theprintf"%d%d%d\n", awin_b+awin_c+awin_j,ap,alose_c+alose_b+alose_j); +printf"%d%d%d\n", alose_c+alose_b+alose_j,ap,awin_b+awin_c+Awin_j); -      $  $      if(Awin_b>=awin_c&&awin_b>=awin_j) printf ("B"); -      if(Awin_c>awin_b&&awin_c>=awin_j) printf ("C"); -      if(Awin_j>awin_c&&awin_j>awin_b) printf ("J"); the  -      if(alose_b>=alose_c&&alose_b>=alose_j) printf ("B");Wuyi      if(alose_c>alose_b&&alose_c>=alose_j) printf ("C"); the      if(alose_j>alose_c&&alose_j>alose_b) printf ("J"); -  Wu     return 0; -}

Pat B 1018. Hammer and scissors cloth (20)